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3 years ago

I need to be answered quickly

Mathematics

2 answers:

Helen [10]3 years ago

7 0

Answer:△JKL∼△STU

When two triangles are similar , then their corresponding sides are proportional and Corresponding angles of one triangle is equal to corresponding angles of another Triangle.

The two Triangles can be similar by following Similarity axiom

Step-by-step explanation:

andreev551 [17]3 years ago

7 0

Answer:

Given

JL=ST

, KL=TU,

<J=<S

∆JKL is CONGRUENT to ∆ SUT.by S.A.S.axiom

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What are the zeros of f(x) = x2 - 12x + 36?

Otrada [13]

Answer:

A X=6 only

Step-by-step explanation:

${x}^{2} - 12x + 36 = 0\\ x {}^{2} - 6x - 6x + 36 = 0 \\ x(x - 6) - 6(x - 6) = 0 \\ (x - 6)(x - 6) = 0 \\ x - 6 = 0 \: \: \: \: \: or \: \: \: \: \: x - 6 = 0 \\ x = 6 \: \: \: \: or \: \: \: \: \: x = 6$

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3 years ago

Will give Brainliest! if right!

Simora [160]

So B) has all the requirements

The vertical line in the box represents the mean which if you add all the numbers and divide by 15 you get 17 and since no other whisker box plot doesn't have 17 as its mean B is the only logical answer

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3 years ago

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What is the total resistance of a parallel circuit that has three loads? Load one has a resistance of 6 ohms. Load two has a res

gizmo_the_mogwai [7]

Answer:

The total resistance of these three resistors connected in parallel is $1.7143\Omega$

Step-by-step explanation:

The attached image has the circuit for finding the total resistance. The circuit is composed by a voltage source and three resistors connected in parallel: $R_1=6\Omega$ , $R_2=3\Omega$ and $R_3=12\Omega$ .

<u>First step: to find the source current</u>

The current that the source provides is the sum of the current that each resistor consumes. Keep in mind that the voltage is the same for the three resistors ( $R_1$ , $R_2$ and $R_3$ ).

$I_{R_1}=\frac{V_S}{R_1}$

$I_{R_2}=\frac{V_S}{R_2}$

$I_{R_3}=\frac{V_S}{R_3}$

The total current is:

$I_S=I_{R_1}+I_{R_2}+I_{R_3}=\frac{V_S}{R_1}+\frac{V_S}{R_2}+\frac{V_S}{R_3}=\frac{R_2\cdot R_3 \cdot V_S+R_1\cdot R_3 \cdot V_S+R_1\cdot R_2 \cdot V_S}{R_1\cdot R_2\cdot R_3}$

$I_S=V_S\cdot \frac{R_2\cdot R_3+R_1\cdot R_3+R_1\cdot R_2}{R_1\cdot R_2\cdot R_3}$

The total resistance ( $R_T$ ) is the source voltage divided by the source current:

$R_T=\frac{V_S}{I_S}$

Now, replace $I_S$ by the previous expression and the total resistance would be:

$R_T=\frac{V_S}{V_S\cdot \frac{R_2\cdot R_3+R_1\cdot R_3+R_1\cdot R_2}{R_1\cdot R_2\cdot R_3}}$

Simplify the expression and you must get:

$R_T=\frac{R_1\cdot R_2\cdot R_3}{R_2\cdot R_3+R_1\cdot R_3+R_1\cdot R_2}$

The last step is to replace the values of the resistors:

$R_T=\frac{(6\Omega )\cdot (3\Omega)\cdot (12\Omega)}{(3\Omega)\cdot (12\Omega)+(6\Omega)\cdot (12\Omega)+(6\Omega)\cdot (3\Omega)}=\frac{12}{7}\Omega=1.7143\Omega$

Thus, the total resistance of these three resistors connected in parallel is $1.7143\Omega$

4 0

3 years ago

What is another way to write |x+3|?

Solnce55 [7]

Answer:

literally 2 other options |-x+3| and x+3

Step-by-step explanation:

The lines in front of the equation is absolute value, so you are basically counting how far it is from zero. It doesn't change the equation.

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3 years ago

How do I find the missing side length?

kykrilka [37]

Adjacent side to angle 60º=2/3
opposite side to angle 60º=b
hypotenuse=a

cos 60º= adjacent side / hypotenuse
cos 60º=(2/3) / a
a=(2/3) / cos 60º=(2/3) / (1/2)=4/3

tan 60º= opposite side / adjacent side
tan 60º=b / (2/3)
b=(2/3)*tan 60º=(2/3)* √3=2√3 /3

Answer:
a=4/3
b=2√3 /3

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3 years ago

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