Multiple-3(x+0.6) and 6(x+2.4) you will get -3x-1.8=6x+14.4 then you add -3x + 6x you will get -9x=14.4+1.8 you add 14.4+1.8 that will give you 16.2 then divide that by -9
Answer:
A
Step-by-step explanation:
It is not B because 7x^2 means multiplying the equation by seven. It isn't C because that would move the graph DOWN seven units. And it's not D because when it is in parenthesis like that, it means that it is a horizontal shift, not vertical.
complementary angles add up to 90°, so therefore we know that ∡A + ∡B = 90°, and also they are in a ratio of 3:6.
![\bf \cfrac{A}{B}=\cfrac{3}{6}\implies \cfrac{A}{B}=\cfrac{1}{2}\implies 2A=\boxed{B} \\\\[-0.35em] ~\dotfill\\\\ A+B=90\implies A+\boxed{2A}=90\implies 3A=90\\\\\\ A=\cfrac{90}{3}\implies \blacktriangleright A=30 \blacktriangleleft \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ 2(30)=B\implies \blacktriangleright 60=B \blacktriangleleft](https://tex.z-dn.net/?f=%5Cbf%20%5Ccfrac%7BA%7D%7BB%7D%3D%5Ccfrac%7B3%7D%7B6%7D%5Cimplies%20%5Ccfrac%7BA%7D%7BB%7D%3D%5Ccfrac%7B1%7D%7B2%7D%5Cimplies%202A%3D%5Cboxed%7BB%7D%0A%5C%5C%5C%5C%5B-0.35em%5D%0A~%5Cdotfill%5C%5C%5C%5C%0AA%2BB%3D90%5Cimplies%20A%2B%5Cboxed%7B2A%7D%3D90%5Cimplies%203A%3D90%5C%5C%5C%5C%5C%5C%20A%3D%5Ccfrac%7B90%7D%7B3%7D%5Cimplies%20%5Cblacktriangleright%20A%3D30%20%5Cblacktriangleleft%0A%5C%5C%5C%5C%5B-0.35em%5D%0A%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%0A2%2830%29%3DB%5Cimplies%20%5Cblacktriangleright%2060%3DB%20%5Cblacktriangleleft)
Answer:
x = sqrt(3)/5 - 9/5 or x = -9/5 - sqrt(3)/5
Step-by-step explanation by completing the square:
Solve for x over the real numbers:
4 (5 x + 9)^2 - 33 = -21
Add 33 to both sides:
4 (5 x + 9)^2 = 12
Divide both sides by 4:
(5 x + 9)^2 = 3
Take the square root of both sides:
5 x + 9 = sqrt(3) or 5 x + 9 = -sqrt(3)
Subtract 9 from both sides:
5 x = sqrt(3) - 9 or 5 x + 9 = -sqrt(3)
Divide both sides by 5:
x = sqrt(3)/5 - 9/5 or 5 x + 9 = -sqrt(3)
Subtract 9 from both sides:
x = sqrt(3)/5 - 9/5 or 5 x = -9 - sqrt(3)
Divide both sides by 5:
Answer: x = sqrt(3)/5 - 9/5 or x = -9/5 - sqrt(3)/5