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3 years ago

11.3 x 3 = 28.25 please show the formula

1 answer:

4 0

65.98 because of it I have no clue how much you want me and you to get me some of my stuff I need you I know I have a good idea of that but I’m still in a little while

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3 years ago

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Which figure has the same area as the parallelogram shown below? A. A triangle with a base of 4 mm and a height of 20 mm B. A tr

Arisa [49]

<h2>Answer: A trapezoid with bases of 6 mm and 14 mm and a height of 8 mm </h2>

The parallelogram in the figure has an area of $80mm^{2}$ , according to the following formula, which works for all rectangles and parallelograms:

$A_{parallelogram}=(b)(h)$ (1)

Where $b$ is the base and $h$ is the height

The<u> area of a triangle</u> is given by the following formula:

$A_{triangle}=\frac{1}{2}(b)(h)$ (2)

So, for option A:

$A_{triangle}=\frac{1}{2}(4mm)(20mm)=40mm^{2} \neq 80mm^{2}$

Now, the <u>area of a trapezoid </u>is:

$A_{trapezoid}=\frac{1}{2}(b_{1}+ b_{2})(h)$ (3)

For option B:

$A_{trapezoid}=\frac{1}{2}(15mm+25mm)(2 mm)=40mm^{2} \neq 80mm^{2}$

For option C:

$A_{trapezoid}=\frac{1}{2}(6mm+14mm)(8 mm)=80mm^{2}$ >>>>This is the correct option!

For option D:

$A_{rectangle}=(30mm)(8mm)=240mm^{2} \neq 80mm^{2}$

<h2>Therefore the correct option is C</h2>

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3 years ago

rita is estimating the height of her office building. The actual height of her office building is 10.7 m. Rita's estimate is 11

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4 years ago

How do i solve the square root of all these problems step by step

Mars2501 [29]

U can simplify each number to the bottom. Then determine which number pair u can take out. Put those outside of the square too sign. Numbers with out a pair must stay inside the square room

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4 years ago

11.3 x 3 = 28.25 please show the formula​

11.3 x 3 = 28.25 please show the formula