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Ainat [17]
2 years ago
5

How do you sketch f’(x) < 0 when x > 0?

Mathematics
1 answer:
Pavel [41]2 years ago
6 0

Answer:

The painting.You'll be in the fourth quarter.

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You watch a football game. The team you cheer for loses 88 yards on four plays in a row. Which expression shows the total loss i
Flauer [41]

Answer:

C. -8 * 4

Step-by-step explanation:

We are given the situation that your team loses 8 yards on four plays in a row. And you are being asked which expression shows the total loss in yards, our key word in this question is "loss" . Meaning that the result has to come out negative.

Therefore , A. is incorrect because -4 * -8 is 36 . Which is positive.

B. is incorrect because it is positive outcome

And D. is incorrect because one it is not the correct property to use and also is very inaccurate in the answer. Also, it is a positive outcome.

Leaving you with C.

8 0
3 years ago
I need help on this.
Natalija [7]

Answer:

h=4 cm

x²=16+36

x =  \sqrt{52}

5 0
2 years ago
Which is a nonpolar molecule? please help!
amm1812
 I suppose the fifth picture is right.
8 0
3 years ago
I need help finding the values of the last boxes shown in the image.
Bingel [31]

The volume of the region R bounded by the x-axis is: \mathbf{\iint_R(x^2+y^2)dA = \int ^{tan^{-1}(4)}_{0} \int^{\frac{2}{cos \theta}}_{0} \ r^3 dr d\theta}

<h3>What is the volume of the solid revolution on the X-axis?</h3>

The volume of a solid is the degree of space occupied by a solid object. If the axis of revolution is the planar region's border and the cross-sections are parallel to the line of revolution, we may use the polar coordinate approach to calculate the volume of the solid.

In the graph, the given straight line passes through two points (0,0) and (2,8).

Therefore, the equation of the straight line becomes:

\mathbf{y-y_1 = \dfrac{y_2-y_1}{x_2-x_1}(x-x_1)}

where:

  • (x₁, y₁) and (x₂, y₂) are two points on the straight line

Thus, from the graph let assign (x₁, y₁) = (0, 0) and (x₂, y₂) = (2, 8), we have:

\mathbf{y-0 = \dfrac{8-0}{2-0}(x-0)}

y = 4x

Now, our region bounded by the three lines are:

  • y = 0
  • x = 2
  • y = 4x

Similarly, the change in polar coordinates is:

  • x = rcosθ,
  • y = rsinθ

where;

  • x² + y² = r²  and dA = rdrdθ

Now

  • rsinθ = 0   i.e.  r = 0 or θ = 0
  • rcosθ = 2 i.e.   r  = 2/cosθ
  • rsinθ = 4(rcosθ)  ⇒ tan θ = 4;  θ = tan⁻¹ (4)

  • ⇒ r = 0   to   r = 2/cosθ
  •    θ = 0  to    θ = tan⁻¹ (4)

Then:

\mathbf{\iint_R(x^2+y^2)dA = \int ^{tan^{-1}(4)}_{0} \int^{\frac{2}{cos \theta}}_{0} \ r^2 (rdr d\theta )}

\mathbf{\iint_R(x^2+y^2)dA = \int ^{tan^{-1}(4)}_{0} \int^{\frac{2}{cos \theta}}_{0} \ r^3 dr d\theta}

Learn more about the determining the volume of solids bounded by region R here:

brainly.com/question/14393123

#SPJ1

5 0
2 years ago
Jess wants to spend less than
Wewaii [24]

The maximum number of packs Jess can buy is 3 packs.

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2 years ago
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