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2 years ago

Please help me with this question!

Mathematics

1 answer:

Ber [7]2 years ago

8 0

I am un able to see the photo please re try so I can help

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When a number is added to 1/5 of itself, the result is 24. The equation that models this problem is n + 1/5n = 24. What is the v

Zielflug [23.3K]

The answer is 20 since 1/5 of 20 is 4, and 20 + 4 = 24.

7 0

3 years ago

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How much would $200 invested at 5% interest compounded monthly be worth after 9years? Round your answer to the nearest cent

Feliz [49]

Answer:

$311.20

Step-by-step explanation:

Here we are required to use the Compound interest formula for finding the Amount at the end of 9th year

The formula is given as

$A=P(1+\frac{r}{n})^{tn}$

Where ,

A is the final amount

P is the initial amount = $200

r is the rate of interest = 5% annual = 0.05

n is the frequency of compounding in a year ( Here it is compounding monthly) = 12

t is the time period = 9

Now we substitute all these values in the formula and solve for A

$A=200(1+\frac{0.05}{12})^{9\times 12}$

$A=200(1+0.00416)^{108}$

$A=200(1.00416)^{108}$

$A=200 \times 1.556$

$A=311.20$

Hence the amount after 9 years will be $311.20

4 0

2 years ago

-3[1+2(4+5)]<br> PLease answer ASAP!!!

vaieri [72.5K]

Answer:

-57

Step-by-step explanation:

<h2><u>Use BOMAS</u></h2>

B- brackets

O- of

M- multiplication

A- addition

S - subtraction

-3[1+2(4+5)]

first solve what is in the brackets

(4+5) = 9

place 9 in the brackets

-3[1+2(9)]

now multiply the 2 and 9

2*9 = 18

-3[1+18)]

1+ 18 = 19

now multiply the (-3) with 19

= <u>-57</u>

4 0

3 years ago

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Write an expression that is equal to 10 using only four 2s and any number of math symbols

diamong [38]

$(4 \times 2) + 2$

8 0

2 years ago

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What is the simplest form of 3^ √27t^9/729?

Natali [406]

Answer:

$\frac{t^{3} }{3}$

Step-by-step explanation:

$\sqrt[3]{\frac{27t^{9} }{729} }$ 27 is a perfect cube for $3^{3}$ and 729 is a perfect cube for $9^{3}$

$\sqrt[3]{\frac{3^{3} t^{9} }{9^{3} } }$ now you can pull out the numbers from under the root, for t (divide the exponent by 3)

$\frac{3}{9}$ $t^{3}$ now simply to $\frac{t^{3} }{3}$

6 0

2 years ago

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