Question

Given angle D= 60 degrees, determine the PERIMETER of triangle ABC.

Answer 1

Answer:

15*(1+root(3))

Step-by-step explanation:

BD=5, BC=5*root(3), you can find it by using trigonometry.

• AC^2+DC^2=AD^2

AC^2=300, AC=10*root(3)

• AB^2+BC^2=AC^2

AB^2=225, AB=15.

Perimeter of ABC is AB+BC+CA=15+5*root(3)+10*root(3).

15(1+root(3))