Given angle D= 60 degrees, determine the PERIMETER of triangle ABC.
1 answer:
Answer:
15*(1+root(3))
Step-by-step explanation:
BD=5, BC=5*root(3), you can find it by using trigonometry.
AC^2=300, AC=10*root(3)
AB^2=225, AB=15.
Perimeter of ABC is AB+BC+CA=15+5*root(3)+10*root(3).
15(1+root(3))
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