We will call an adult ticket <em>a</em>, and a child ticket <em>c</em>.
Since they sold 60 tickets in total, we can form the equation:
a + c = 60
We can also say that the sum of money from the adult tickets and child tickets combined is 460.
Thus we can say
11a + 6c = 460
Now, we must solve our system.
a + c = 60
11a + 6c = 460
6a + 6c = 360
11a + 6c = 460
-5a = -100
a = 20
Thus, (20) + c = 60
c = 40
a = 20 and c = 40
Step-by-step explanation:
A. part 1: $1.49 for 6 pencils
1 pencil would cost $1.49 / 6 = $0.24833(5s.f.) = $0.25 (nearest cent)
part 2: $4.60 for 20 pencils
1 pencil would cost $4.60 / 20 = $0.23
best value: part 2 (20pencil pack)
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On the 15th day
Explanation
You have to find which multiple they have the same and that would be 15
3: 3, 6, 9, 12, 15, 18, 21 and so on
5: 5, 10, 15, 20, 25 and so on