Answer:
a total of 24 presents can be wrapped
Step-by-step explanation:
6 x 3 = 18 feet of ribbon
18 x 12 = 216 inches of ribbon
216/9 = 24 presents can be wrapped
Answer:
answer b
Step-by-step explanation:
hope that helps
Answer:
![A=292.53~m^2](https://tex.z-dn.net/?f=A%3D292.53~m%5E2)
Step-by-step explanation:
<u>Area of a Compound Shape</u>
The shape shown in the image is made of two shapes: Half a circle of radius 8 m and a triangle of base 24 m and height 16 m.
The area of a circle of radius r is:
![A_c = \pi r^2](https://tex.z-dn.net/?f=A_c%20%3D%20%5Cpi%20r%5E2)
The area of a triangle of base b and height h is:
![\displaystyle A_t=\frac{b.h}{2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20A_t%3D%5Cfrac%7Bb.h%7D%7B2%7D)
Calculate the area of the circle:
![A_c = \pi 8^2](https://tex.z-dn.net/?f=A_c%20%3D%20%5Cpi%208%5E2)
![A_c = 64\pi](https://tex.z-dn.net/?f=A_c%20%3D%2064%5Cpi)
Area of half the circle:
![A_c/2 = 32\pi~m^2](https://tex.z-dn.net/?f=A_c%2F2%20%3D%2032%5Cpi~m%5E2)
Area of the triangle:
![\displaystyle A_t=\frac{24\cdot 16}{2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20A_t%3D%5Cfrac%7B24%5Ccdot%2016%7D%7B2%7D)
![A_t=192~m^2](https://tex.z-dn.net/?f=A_t%3D192~m%5E2)
The area of the shaded shape is:
![A=32\pi~m^2+192~m^2](https://tex.z-dn.net/?f=A%3D32%5Cpi~m%5E2%2B192~m%5E2)
Substituting the value of pi:
![\mathbf{A=292.53~m^2}](https://tex.z-dn.net/?f=%5Cmathbf%7BA%3D292.53~m%5E2%7D)