5 (2x – 1) –7 = 2 (x – 3)

Mathematics

1 answer:

Sladkaya [172]2 years ago

7 0

Answer:

x−3=x−3

Step-by-step explanation:

Evaluate (2x−1)−7, then set it equal to 2.

Subtract 7 from −1 = 2x−8

Solve 2x−8=2.

Move all terms not containing x to the right side of the equation.

Add 8 to both sides of the equation=2x=2+8

Add 2 and 8=2x=10

Divide each term by 2 and simplify.

Divide each term in 2x=10 by 2=2x/2=10/2

Cancel the common factor of 2

Cancel the common factor=10/2

Divide x by 1=x=10/2

Divide 10 by 2=x=5

Remove parentheses=x−3

List all of the solutions.

(2x−1)−7=2=x=5

x−3=x−3

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Need help pls<br>thank you in advance

ira [324]

Answer:

<u />

$\textsf{Mean}\:\overline{X}=\sf \dfrac{\textsf{sum of all the data values}}{\textsf{total number of data values}}$

$\implies \sf Mean\:(Nilo)=\dfrac{5+6+14+15}{4}=\dfrac{40}{4}=10$

$\implies \sf Mean\:(Lisa)=\dfrac{8+9+11+12}{4}=\dfrac{40}{4}=10$

<h3><u>Standard Deviation</u></h3>

$\displaystyle \textsf{Standard Deviation }s=\sqrt{\dfrac{\sum X^2-\dfrac{(\sum X)^2}{n}}{n-1}}$

$\begin{aligned}\displaystyle \textsf{Standard Deviation (Nilo)} & =\sqrt{\dfrac{(5^2+6^2+14^2+15^2)-\dfrac{(5+6+14+15)^2}{4}}{4-1}}\\\\& = \sqrt{\dfrac{482-\dfrac{40^2}{4}}{3}}\\\\& = \sqrt{\dfrac{82}{3}}\\\\& = 5.23\end{aligned}$

$\begin{aligned}\displaystyle \textsf{Standard Deviation (Lisa)} & =\sqrt{\dfrac{(8^2+9^2+11^2+12^2)-\dfrac{(8+9+11+12)^2}{4}}{4-1}}\\\\& = \sqrt{\dfrac{410-\dfrac{40^2}{4}}{3}}\\\\& = \sqrt{\dfrac{10}{3}}\\\\& = 1.83\end{aligned}$

<h3><u>Summary</u></h3>

Nilo has a mean score of 10 and a standard deviation of 5.23.

Lisa has a mean score of 10 and a standard deviation of 1.83.

The <u>mean</u> scores are the <u>same</u>.

Nilo's standard deviation is higher than Lisa's. Therefore, Nilo's test scores are more <u>spread out</u> that Lisa's, which means Lisa's test scores are more <u>consistent</u>.

5 0

1 year ago

3( 3v +5 ) = 39<br> Solve this problem

V125BC [204]

Answer:

V= 8/3

Step-by-step explanation: