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Ainat [17]
3 years ago
15

A track coach is trying to improve the 50 -meter-dash times of the track team. He times each student and then implements a month

-long training program. At the end of the program, he timed each of the students again. The box plots show the number of seconds it took the students to run the 50 -meter-dash before and after the program. Using the plots, how much did the median change?

Mathematics
1 answer:
Aleks04 [339]3 years ago
8 0

Answer:

-5

Step-by-step explanation:

Given the two box plots showing the number of seconds the students completes the 50-meter-dash race before and after the program, we are to determine the difference between the median value of seconds before and after the program.

Median in a box plot is represented by the vertical line that divides the rectangular box in a box plot.

Thus, the median before the program = 15 seconds

The Median after the program = 10 seconds

The median change = 10 - 15 = -5 seconds.

This means, after the program, most of the students now finish the 50-meter-dash faster, about 5 seconds less the former seconds used before the program.

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Answer:

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<u>Step 2: Use sin formula to find H</u>

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<em>32/sin 74 = b/sin 39</em>

b = 20.9 feet.

The height of the tower is 20.9 feet.

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Step-by-step explanation:

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Plz help asap this table represent a quadratic function with a vertex a (1,2) what is the average rate of change for the interva
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Answer:

9

Step-by-step explanation:

Given that (1, 2) is the vertex of the function represented by the table of values above, the rate of change for the interval from x = 5 to x = 6.

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f(6) = ?

=>Find f(6) using the vertex form function, f(x) = a(x - h)² + k

Where, h and k are the given vertex of the function = (1, 2).

h = 1, k = 2

Thus,

f(x) = a(x - 1)² + 2

Find the value of a by using any of the points given in the table.

Using (3, 6), we have the following,

6 = a(3 - 1)² + 2

6 = a(2)² + 2

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Subtract 2 from both sides

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