The block most effectively keep a sprite from moving off the screen if if on edge, bounce. Hence option B is correct.
<h3>
What is screen?</h3>
Screen is defined as a portable or stationary object that offers shelter, acts as a partition, etc., and often consists of a covered frame. Screening is defined as the procedure of locating or choosing individuals from a community according to one or more selection criteria.
The block will kept more perfectly if one of the edge there is bounce so that the box will not fall from the sprite.
Thus, the block most effectively keep a sprite from moving off the screen if if on edge, bounce. Hence option B is correct.
To learn more about screen, refer to the link below:
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Hi! Did you forget to add something to this?
Answer:
Option B is the correct answer.
Explanation:
- In the above code, the loop will execute only one time because the loop condition is false and it is the Do-While loop and the property of the Do-while loop is to execute on a single time if the loop condition is false.
- Then the statement "x*=20;" will execute one and gives the result 200 for x variable because this statement means "x=x*20".
- SO the 200 is the answer for the X variable which is described above and it is stated from option B. Hence it is the correct option while the other is not because--
- Option A states that the value is 10 but the value is 200.
- Option C states that this is an infinite loop but the loop is executed one time.
- Option D states that the loop will not be executed but the loop is executed one time
<span>make periodic adjustments on an as-needed basis. </span>
