1) area of a cicular pool
area of a circle=πr^2 d=2.5 then r=2.5/2
A=3.14 *(2.5/2)^2
A=4.906m^2 A=4.9m^2
2) arae of a coin
<span>(if i read it right d=15mm?)
</span>A=πr^2 d=15 then r=15/2
A=3.14*(15/2)^2 =176.6mm^2
Rest all are same problems u try to solve it
Answer:
x=1
Z=35.4965
assuming you want y to be the height, y=5.916
Step-by-step explanation:
x/height=height/35
35x=y^2
using Pythagorean theorem
y^2+x^2=6^2
y^2+35^2=z^2
substituting for y^2
35x+x^2=6^2
x^2+35x-36=0
(x+36)(x-1)=0
x=1
y^2+x^2=6^2
substitute
y^2+1=36
y^2=35
y=5.916
y^2+35^2=z^2
substitute
35+1225=z^2
z^2=1260
z=35.4965
Answer:
Step-by-step explanation:
(4/5)n = (2/3)
move 4/5 to the right
n = (2/3)/(4/5)
n = 5/6
Answer: -1/2 or -0.5.
Explanation: -2- -1, -6- -2= -0.5
Answer:
They are both 63 Inches/ Lengths apart.
Step-by-step explanation:
<em>You see when it comes to cm2 inches and lengths You must always Analyze your work and figure out if you can seperate the two among themselves equally. 81 Goes into 144. 63 plus equation.</em>