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3 years ago

PLEASE HELP ME WITH THIS ONE QUESTION

Mathematics

1 answer:

vesna_86 [32]3 years ago

6 0

Answer:

option C

Step-by-step explanation:

Total number of items = 5

Number of items to choose = 2

Therefore, the number of combinations is

$5C_2 = \frac{5 \times 4}{1 \times 2} = 10$

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3 years ago

What is the product of (2x-7) and (3x + 3)?

eduard

<h3>✒️EVALUATION </h3>

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$\large\sf\underline{Problem:}$

What is the product of (2x-7) and (3x + 3)?

A. 6x2 + 15x-21
B. 6x2 - 15x - 21
C. 6x2 + 15x + 21
D. 6x2 - 15x + 21

==================================

$\large\sf\underline{Answer:}$

$\qquad \qquad \huge \rm Letter\:B.$

*Please read and understand my solution. Don't just rely on my direct answer*

==================================

$\large\sf\underline{Solution:}$

Here we have the given choices:

A. 6x2 + 15x-21
B. 6x2 - 15x - 21
C. 6x2 + 15x + 21
D. 6x2 - 15x + 21

Solve this equation using the distributive property,where you multiply each term to get the number.

$\begin{gathered} \rm2x - 7 = \boxed{ 6} \: \bigg| \small\boxed{\: 6 {x}^{2} } \\ \rm (7)(3) = \boxed{21} \bigg | \boxed{\: 21 x} \\ \\ \qquad \rm6x^{2}+(6x- 21x)-21 \\ \qquad \boxed{ \rm6 {x}^{2} + 15x - 21}\end{gathered}$

Therefore, the correct option is letter B.

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3 0

2 years ago

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