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Juliette [100K]
3 years ago
12

PLEASE HELP ME WITH THIS ONE QUESTION

Mathematics
1 answer:
vesna_86 [32]3 years ago
6 0

Answer:

option C

Step-by-step explanation:

Total number of items = 5

Number of items to choose = 2

Therefore, the number of combinations is

                                                       5C_2 = \frac{5 \times 4}{1 \times 2} = 10

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How to factor 2n^2+3n-9 without splitting the middle term
kozerog [31]
2n^2+3n-9= \\\\ a=2 \\ b=3 \\ c=-9 \\\\ \Delta= 3^2-4*2*(-9)=9+72\to\boxed{81} \\\\ x_1;x_2=\frac{-3 +\-\sqrt{81}}{2*2}= \frac{-3+/- 9}{4} \\\\ x_1=\frac{-3+9}{4}=\frac{6}{4}\to\boxed{\frac{3}{2}} \\\\ x_2=\frac{-3-9}{4}=\frac{-12}{4}\to\boxed{-4} \\\\ 2n^2+3n-9=(x-\frac{3}{2})(\x+4)
7 0
3 years ago
Solve l 3x-7 l = 2
Lelechka [254]

Answer:

1) Solutions are x = 3 and x = 5/3

2) Solution are x ≤ 13/2 and  x ≤ -3/2

Step-by-step explanation:

1) Given absolute inequality,

|3x-7| = 2

⇒ 3x - 7 = ± 2

⇒ 3x = 7 ± 2

\implies x=\frac{7\pm 2}{3}

x=\frac{7+2}{3}\text{ or }x=\frac{7-2}{3}

\implies x = 3\text{ or }x=\frac{5}{3}

2) l 2x-5 l ≤ 8

⇒  2x-5  ≤ ±8

⇒   2x ≤ 5 ± 8

\implies x\leq \frac{5\pm 8}{2}

x\leq \frac{5+8}{2}\text{ or }x\leq \frac{5-8}{2}

\implies x \leq \frac{13}{2}\text{ or }x\leq-\frac{3}{2}

8 0
3 years ago
Read 2 more answers
WILL GIVE BRAINLIEST!
Elan Coil [88]
The answer will be 4000
5 0
3 years ago
Find the lentgh of the missing side
adell [148]

Answer:

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8 0
3 years ago
Help? I'm not exactly sure how to do this :/
uranmaximum [27]
What you do is plug the z value (first column) into the formula (second column), and solve for y. For instance, the first one would be y = -1-2, or -3. The x would be the x in the ordered pair, and the final ordered pair would be (-1,-3). Make sense?
6 0
3 years ago
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