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3 years ago

PLEASE HELP ME WITH THIS ONE QUESTION

Mathematics

1 answer:

vesna_86 [32]3 years ago

6 0

Answer:

option C

Step-by-step explanation:

Total number of items = 5

Number of items to choose = 2

Therefore, the number of combinations is

$5C_2 = \frac{5 \times 4}{1 \times 2} = 10$

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How to factor 2n^2+3n-9 without splitting the middle term

kozerog [31]

$2n^2+3n-9= \\\\ a=2 \\ b=3 \\ c=-9 \\\\ \Delta= 3^2-4*2*(-9)=9+72\to\boxed{81} \\\\ x_1;x_2=\frac{-3 +\-\sqrt{81}}{2*2}= \frac{-3+/- 9}{4} \\\\ x_1=\frac{-3+9}{4}=\frac{6}{4}\to\boxed{\frac{3}{2}} \\\\ x_2=\frac{-3-9}{4}=\frac{-12}{4}\to\boxed{-4} \\\\ 2n^2+3n-9=(x-\frac{3}{2})(\x+4)$

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3 years ago

Solve l 3x-7 l = 2

Lelechka [254]

Answer:

1) Solutions are x = 3 and x = 5/3

2) Solution are x ≤ 13/2 and x ≤ -3/2

Step-by-step explanation:

1) Given absolute inequality,

|3x-7| = 2

⇒ 3x - 7 = ± 2

⇒ 3x = 7 ± 2

$\implies x=\frac{7\pm 2}{3}$

$x=\frac{7+2}{3}\text{ or }x=\frac{7-2}{3}$

$\implies x = 3\text{ or }x=\frac{5}{3}$

2) l 2x-5 l ≤ 8

⇒ 2x-5 ≤ ±8

⇒ 2x ≤ 5 ± 8

$\implies x\leq \frac{5\pm 8}{2}$

$x\leq \frac{5+8}{2}\text{ or }x\leq \frac{5-8}{2}$

$\implies x \leq \frac{13}{2}\text{ or }x\leq-\frac{3}{2}$

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3 years ago

Read 2 more answers

WILL GIVE BRAINLIEST!

Elan Coil [88]

The answer will be 4000

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Answer:

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Help? I'm not exactly sure how to do this :/

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3 years ago