The point-slope form of the equation for a line can be written as
... y = m(x -h) +k . . . . . . . for a line with slope m through point (h, k)
Your function gives
... f'(h) = m
... f(h) = k
a) The tangent line is then
... y = 5(x -2) +3
b) The normal line will have a slope that is the negative reciprocal of that of the tangent line.
... y = (-1/5)(x -2) +3
_____
You asked for "an equation." That's what is provided above. Each can be rearranged to whatever form you like.
In standard form, the tangent line's equation is 5x -y = 7. The normal line's equation is x +5y = 17.
Answer:what is 86-50=36 us the tax rate
Step-by-step explanation:
Answer:
12
Step-by-step explanation:
y=c that make 0 and then i mulitply -1 to -12
then i did the opposite for 360 time -12 that 700 and then i devided and got 12
Answer:
1.9
Step-by-step explanation:
7.6/4= 1.9
1.9*1= 1.9
ans is 1.9 pints
