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3 years ago

The table below represents a linear function f(x) and the equation represents a function g(x):

Mathematics

1 answer:

lana66690 [7]3 years ago

5 0

Answer:

Step-by-step explanation:

Part A

for f(x) slope between points (-1,-6) and (1,0)

m= y2-y1/x2-x1 = -6-0/-1-1 = -6/-2= 3

for g(x) slope m=4 because we compare to equation y=mx+b the given equation g(x)=4x-5

The slope of f(x) is 3 and the slope g(x) is 4 so the line of g(x) is steeper

part B

The y intercept for g(x) is (0, -5)

The equation of f(x) can be found

y-y1 =m(x-x1) take any point for example point (1,0)

y-1 =3(x-0)

y=3x+1 so the y-intercept is at (0,1)

The y-intercept for f(x) is greater at y=1 then the one of g(x) at y=-5

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Help me please asap!

ad-work [718]

Answer:

Step-by-step explanation:

First you must notice each of them share an x value in the exponent. So with that being said x is your GCF or in otherwords greatest common factor.

So you have an x(x^3-6x^2+9x)

you must take x from all of them inside the ( )

because x is your gcf :)

So x(x^2-6x+9) Now you use the trail and method error

to get (x-3 )(x-3 )you need two numbers that multiply to 9 but add up to -6 so... that would hmmm -3 and -3 cause -3*-3=9 and -3+-3=-6

don't forget your GCF bring it down because it's always in your answer

x(x-3)(x-3)

or..

x(x-3)^2 both are the same thing

ANSWER CAN BE

x(x-3)(x-3) OR x(x-3)^2

Both are the same thing just written different! You're welcome!

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4 years ago

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mylen [45]

Answer:

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3 years ago

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Find the area of the regular polygon, 6 sides, 12 in, rounded to the nearest tenth

olga nikolaevna [1]

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4 years ago

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A pair of dice is rolled. What is the probability that the sum of the two dice will less than 4 given that the first die rolled

leonid [27]

1/6 because the only way the sum can be less than 4 if the first die is a 2 is if the second die is a 1.

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3 years ago

If you roll a dice four times, what is the chance that you roll two 3s?

Rufina [12.5K]

Answer:

11.57%

Step-by-step explanation:

The probability of rolling two 3s is the product of the probability of rolling two 3s and two not-3s, and the number of ways that combination of rolls can appear.

<h3>combinations of rolls</h3>

Of the four die rolls, we want two of them to be 3s. The 3s can appear anywhere in the sequence. For example, we could have 33xx, or xx33, or any of a number of other combinations (where x is a "not 3"). The total number of ways two 3s can appear an a sequence of 4 rolls is ...

C(4, 2) = 4!/(2!(4 -2)!) = 4·3/(2·1) = 6

<h3>probability of two 3s and two not-3s</h3>

The probability of rolling a 3 on a fair 6-sided die with one face labeled 3 is presumed to be 1/6. Then the probability of rolling something else is ...

1 -1/6 = 5/6

So, two 3s and two not-3s in a given sequence have a probability of ...

(1/6)(1/6)(5/6)(5/6) = 25/1296

<h3>two 3s in 4 rolls</h3>

The probability that four rolls of the die will show exactly two 3s is the product of the probability it can happen and the number of ways it can happen:

(25/1296) × 6 = 25/216 ≈ 11.57%

_____

The attachment shows the probability function of a calculator gives the same result.

3 0

3 years ago