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fiasKO [112]
3 years ago
14

Help me please I’ll make it brainliest !!!!!

Mathematics
1 answer:
gladu [14]3 years ago
8 0

Answer:

The answer is the first option

Step-by-step explanation:

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HELP PLEASE DUE IN 30 MINS!!!!!!!!!
pshichka [43]

Step-by-step explanation:

25 = 3.75

\frac{25}{3.75}

1 = 0.15

90 = 12.60

1 = 0.14

hope it helps you ☺️

7 0
3 years ago
Read 2 more answers
Sarah earned a 4% commission on all of her sales in March. Her total sales were 80,000 in March, How many money did she earn. Fr
o-na [289]

Answer:

Amount of commission = 3,200

Step-by-step explanation:

Given:

Total sales value = 80,000

Rate of commission = 4% on sales

Find:

Amount of commission

Computation:

Amount of commission = Total sales value x Rate of commission

Amount of commission = 80,000 x 4%

Amount of commission = 3,200

8 0
3 years ago
Plz help due tonight
dsp73

Answer:

33 is the right answer

Step-by-step explanation:

May this help you

3 0
3 years ago
Read 2 more answers
Choose the axiom that allows x(10) to be written 10x.
Alina [70]
I think the correct answer from the choices listed above is the last option. The axiom that allows x(10) to be written 10x would be the commutative property of multiplication. It <span>states that numbers can be added or multiplied in any order. Hope this answers the question. Have a nice day.</span>
6 0
3 years ago
Read 2 more answers
The core melt- down and explosions at the nuclear reactor in Chernobyl in 1986 released large amounts of strontium-90, which dec
elena-14-01-66 [18.8K]

If S(t) is the amount of strontium-90 present in the area in year t, and it decays at a rate of 2.5% per year, then

S(t+1)=(1-0.025)S(t)=0.975S(t)

Let S(0)=s be the starting amount immediately after the nuclear reactor explodes. Then

S(t+1)=0.975S(t)=0.975^2S(t-1)=0.975^3S(t-2)=\cdots=0.975^{t+1}S(0)

or simply

S(t)=0.975^ts

So that after 50 years, the amount of strontium-90 that remains is approximately

S(50)=0.975^{50}s\approx0.282s

or about 28% of the original amount.

We can confirm this another way; recall the exponential decay formula,

S(t)=se^{kt}

where t is measured in years. We're told that 2.5% of the starting amount s decays after 1 year, so that

0.975s=se^k\implies k=\ln0.975

Then after 50 years, we have

S(50)=se^{50k}\approx0.282s

5 0
3 years ago
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