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3 years ago

Question 6 of 10

Mathematics

1 answer:

Greeley [361]3 years ago

7 0

I believe the answer is V = 216^3

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Solve the triangle If b=16 and B=55

Romashka-Z-Leto [24]

Answer:

Just use the law of Sine

To find A degree's & side a as

A degrees equals 180 - 90 - 55 = 35

Sin(35°) / a = Sin(55°) / 16

16 * [sin(35°)] = a * [sin(55°)]

4 0

4 years ago

Read 2 more answers

Given that -5 is a zero of the function f(x) = x^3 + x^2 - 14x + 30 find the remaining zeros

vampirchik [111]

Since the factors are (x+5)(x^2-4x+6)

the zeros would be 2+i√2 and 2−i√2

5 0

3 years ago

The principal observes 8th grade the following day. Of the 120 students, 42 brought their lunch from home, 72 purchased lunches,

Rama09 [41]

Answer:

i pretty sure i do not know that answer to be honest

Step-by-step explanation:

i believe this because i dont know anything about this im still lost

8 0

2 years ago

ANSWER ASAP PLZ!!

Vikentia [17]

$\text{If is}\\\\\left\{\begin{array}{ccc}0.2-0.3y=4\\2.3x-y=1.2\end{array}$

Answer:

$\large\boxed{\left(-\dfrac{344}{69},\ -\dfrac{38}{3}\right)}$

Step-by-step explanation:

$\left\{\begin{array}{ccc}0.2-0.3y=4\\2.3x-y=1.2&\text{multiply both sides by (-0.3)}\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}0.2-0.3y=4\\-0.69x+0.3y=-0.36\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad-0.69x+0.2=3.64\qquad\text{subtract 0.2 from both sides}\\.\qquad-0.69x=3.44\qquad\text{divide both sides by (-0.69)}\\.\qquad x=-\dfrac{3.44\cdot100}{0.69\cdot100}\\.\qquad \boxed{x=-\dfrac{344}{69}}\\\\\text{Calculate the value of y from first equation:}$

$0.2-0.3y=4\qquad\text{subtract 0.2 from both sides}\\-0.3y=3.8\qquad\text{divide both sides by (-0.3)}\\y=-\dfrac{3.8\cdot10}{0.3\cdot10}\\\boxed{y=-\dfrac{38}{3}}$

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$\text{If is}\\\\\left\{\begin{array}{ccc}0,2x-0,3y=4\\2.3x-y=1.2\end{array}\right$

Answer:

$\large\boxed{\left(-\dfrac{52}{7},\ -\dfrac{128}{7}\right)}$

Step-by-step explanation:

$\left\{\begin{array}{ccc}0.2x-0.3y=4&\text{multiply both sides by 10}\\2.3x-y=1.2&\text{multiply both sides by 10}\end{array}\right\\\\\left\{\begin{array}{ccc}2x-3y=40&\text{multiply both sides by (-10)}\\23x-10y=12&\text{multiply both sides by 3}\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}-20x+30y=-400\\69x-30y=36\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad49x=-364\qquad\text{divide both sides by 49}\\x=-\dfrac{364:7}{49:7}\\.\qquad\boxed{x=-\dfrac{52}{7}}$

$2\left(-\dfrac{52}{7}\right)-3y=40\\-\dfrac{104}{7}-3y=40\qquad\text{multiply both sides by 7}\\-104-21y=280\qquad\text{add 104 to both sides}\\-21y=384\qquad\text{divide both sides by (-21)}\\y=-\dfrac{384:3}{21:3}\\\boxed{y=-\dfrac{128}{7}}$

7 0

4 years ago

I'm picking a number between 1-20. I add 5, then I times the number by 3. Lastly I takeaway it by 15. My answer is 42.

Pani-rosa [81]

So (x + 5)*3 - 15 = 42
so the answer is
42 + 15 = 15 + 3x
so solving for x:
x = 14

6 0

3 years ago

Read 2 more answers