9514 1404 393
Answer:
491,400 ft·lb
Step-by-step explanation:
The mass of the water is ...
M = Vρ = LWHρ = (25 ft)(15 ft)(7 ft)(62.4 lb/ft³) = 163,800 lb
The average depth is 3 ft, so the work required is equivalent to that required to raise this mass 3 ft.
W = (3 ft)(163,800 lb) = 491,400 ft·lb
Answer:
p+m=46
46:4=11.5
Step-by-step explanation:
good luck
What do you need help with maybe i can help.
It is 19%!! :) an explanation is:
We assume, that the number 2500 is 100% - because it's the output value of the task.
2. We assume, that x is the value we are looking for.
3. If 100% equals 2500, so we can write it down as 100%=2500.
4. We know, that x% equals 475 of the output value, so we can write it down as x%=475.
5. Now we have two simple equations:
1) 100%=2500
2) x%=475
where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:
100%/x%=2500/475
6. Now we just have to solve the simple equation, and we will get the solution we are looking for.
7. Solution for 475 is what percent of 2500
100%/x%=2500/475
(100/x)*x=(2500/475)*x - we multiply both sides of the equation by x
100=5.2631578947368*x - we divide both sides of the equation by (5.2631578947368) to get x
100/5.2631578947368=x
19=x
x=19
now we have:
475 is 19% of 2500
The measures of variability for each class are listed:
Class A: Class B:
Range : 30 Range: 30
IQR: 12.5 IQR: 20.5
MAD: 7.2 MAD: 9.2
The interquartile range and the mean absolute deviations for class B are larger number therefore indicating that there is more variability in that data set.
