Question

Need help for Geo very Urgent please

Answer 1

Direct answers :

In triangle 1 :

$\color{plum}\tt \: \bold{\tt m∠1 = 77.7°}$

In triangle 2 :

$\color{plum}\bold{\tt \: m∠B =63 °}$

$\color{plum}\bold{\tt \: m∠C =63° }$

In triangle 3 :

$\color{plum}\bold{\tt \: m∠1 = 40° }$

$\color{plum}\bold{\tt \: m∠2 = 28°}$

Steps to derive the correct measurement of each of the angles :

In triangle 1 :

Given :

• m∠2 = 52.2°
• m∠3 = 50.1°

Sum of all angles in a triangle = 180°

Which means :

$=\tt 180 - (52.2 + 50.1)$

$=\tt 180 - 102.3$

$= \tt77.7°$

Thus, the measure of angle 1 = 77.7°

Since the sum of all angles (77.7+52.2+50.1=180°) equals 180° we can conclude that we have found out the correct value of angle 1.

Therefore, the m∠1 = 77.7°

In triangle 2 :

Given :

• m∠A = 54°
• m∠B = m∠C

Let the measure of angle B be x.

Then, the measure of angle C will also be x.

Which means the sum of angle B and C will be equal to 2x.

That means :

$=\tt 54 + 2x = 180$

$= \tt180 - 54 = 2x$

$=\tt 2x = 126$

$=\tt x = \frac{126}{2}$

$=\tt x = 63$

Thus, the measure of Angle B = 63°

Measure of angle C = 63°

In triangle 3 :

Given :

• m∠3 = 112°
• Measure of exterior angle = 140°

Which means :

= m∠2 + 112° = 140° (exterior angle property)

$= \tt140 - 112 = ∠2$

$= \tt \: m∠2 = 28°$

Thus, the measure of angle 2 = 28°

= m∠1 + m∠2 + m∠3 = 180°

$=\tt m∠1 + 112 + 28 = 180$

$=\tt m∠1 + 140 = 180$

$= \tt \: m∠1 = 180 - 140$

$= \tt \: m∠1 = 40°$

Thus, the measure of angle 1 = 40°