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Yanka [14]
3 years ago
10

Can someone plzzz help me!!!

Mathematics
2 answers:
anyanavicka [17]3 years ago
8 0

Answer:

(-3,-1)

Step-by-step explanation:

elena-s [515]3 years ago
3 0
The answer is (-3,-1) I think
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What is 1,455.8 x 4,628.9?
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Answer:

6738752.62

Step-by-step explanation:

1,455.8 x 4,628.9=6738752.62

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2 years ago
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Write a rule for the nth term of the geometric sequence for which a1=−6 and a5=−486
patriot [66]

The geometric rule for the nth term of the geometric sequence for which a1 =−6 and a5=−486 is -6 × 3^(n - 1)

<h3>The nth term of a geometric sequence</h3>

First term, a1 = -6

Fifth term, a5 = -486

a5 = ar^(n - 1)

-486 = -6 × r^(5-1)

-486 = -6r⁴

r⁴ = -486 / 6

r⁴ = 81

r = 4√81

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Geometric rule:

nth term = ar^(n-1)

nth term = -6 × 3^(n - 1)

Learn more about geometric sequence:

brainly.com/question/24643676

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7 0
2 years ago
PLEASE HELP/ANSWER! From 1980 to 1990, Lior’s weight increased by 25%. If his weight was k kilograms in 1990, what was it in 198
Elena-2011 [213]

The weight in 1980 is \frac{4k}{5} kilograms

<em><u>Solution:</u></em>

From 1980 to 1990, Lior’s weight increased by 25%

His weight is "k" kilograms in 1990

<em><u>To find: weight in 1980</u></em>

This is a percentage increase problem

Let "x" be the weight in kilograms in 1980

<em><u>The percentage increase is given by formula:</u></em>

\text{Percentage increase } = \frac{\text{Final value - initial value}}{\text{initial value}} \times 100

Here,

Initial value in 1980 = x

Final value in 1990 = k

Percentage increase = 25 %

<em><u>Substituting the values in formula,</u></em>

25 = \frac{k-x}{x} \times 100\\\\25x = 100(k-x)\\\\x = 4(k-x)\\\\x = 4k - 4x\\\\5x = 4k\\\\x = \frac{4k}{5}

Thus the weight in kilograms in 1980 is \frac{4k}{5}

7 0
4 years ago
Please help me quickly
Scilla [17]
Divide 4 to both sides of the equation
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3 years ago
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A rectangular room has a perimeter of 70m and is 20m long write an equation to represent the area
sveta [45]
Do you have any answer choices 
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3 years ago
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