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Tanya [424]
2 years ago
5

In your own words, what is the difference between an equation and an expression?

Mathematics
2 answers:
LekaFEV [45]2 years ago
8 0
The difference between a Equation and expression is that a Equation has a equal sign( = ) while a expression does not.
otez555 [7]2 years ago
6 0

Answer:

An expression doesn't have an defiant answer. While an equation does.

Yes, you can copy and paste saying its your own words.

Hope this helps! <3

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Which represents a quadratic function? ​
netineya [11]

Answer:

b is the answer

Step-by-step explanation:

f(x) = ax^2 + bx + c

3 0
3 years ago
Read 2 more answers
Solve each equation for the indicated variable g=a+c+b,for a
Mariulka [41]

Answer:

a= g-b-c

Step-by-step explanation:

g=a+c+b

g-b=a+c

g-b-c= a

a= g-b-c

3 0
3 years ago
Find the area of the rectangle.
kirill115 [55]

Answer:

40 units²

Step-by-step explanation:

Area of Rectangle: A = lw

Step 1: Define variables

<em>l</em> = 8

<em>w</em> = 5

Step 2: Substitute and evaluate

A = 8(5)

A = 40 u²

4 0
3 years ago
Speeding: On a stretch of Interstate-89, car speed is a normally distributed variable with a mean of 69.1 mph and a standard dev
Alborosie

Answer: 11.9%

Step-by-step explanation:

Given :  On a stretch of Interstate-89, car speed is a normally distributed variable with \mu=69.1 mph and \sigma=3.3 mph.

Let x be a random variable that represents the car speed.

Since , z=\dfrac{x-\mu}{\sigma}

z-score corresponds x = 73 , z=\dfrac{73-69.1}{3.3}\approx1.18

Required probability :

\text{P-value }: P(x>73)=P(z>1.18)\\\\=1-P(z

[using z-value table.]

Hence, the approximate percentage of cars are traveling faster than you = 11.9%

8 0
3 years ago
Please help me with both questions!
vova2212 [387]

Answer:

maximum area will be 1058 square yards

maximum height will be 81 feet

Step-by-step explanation:

P = 2L +2W

but in this case it will be P= L+2W and P=92 yards

L+2W = 92

Solve for L , L = 92-2W

The area of rectangle A = L x W

Plug in L and simplify: A = (92-2W)W =92W -2W²

Plot in your calculator  and  look for maximum so when the width is 23 yards maximum area will be 1058 square yards.

Second problems is the maximum height of the rocket. Maximum will be at the vertex of the upside-down parabola.

7 0
2 years ago
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