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3 years ago

In your own words, what is the difference between an equation and an expression?

Mathematics

2 answers:

LekaFEV [45]3 years ago

8 0

The difference between a Equation and expression is that a Equation has a equal sign( = ) while a expression does not.

otez555 [7]3 years ago

6 0

Answer:

An expression doesn't have an defiant answer. While an equation does.

Yes, you can copy and paste saying its your own words.

Hope this helps! <3

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A table and 8 chairs weigh 234.68 lb together. If the table weighs 157.84 lb, what is the weight of one chair in pounds?

Trava [24]

You subtract 234.68 and 157.84 and you get 76.84lb

5 0

3 years ago

Suppose we roll a fair six-sided die and sum the values obtained on each roll, stopping once our sum exceeds 285. Approximate th

OlgaM077 [116]

Answer:

Step-by-step explanation:

Probability is given by number of possible outcomes ÷ number of total outcomes

Assuming we stop rolling the six-sided die once our sum is 290 ( exceeds 285)

Number of possible outcomes = 75, number of total outcomes = 290

Probability (75 rolls are needed to get this sum) = 75/290 = 0.259

Probability (more than 75 rolls are needed to get this sum) = 1 - 0.259 = 0.741

Probability (at least 75 rolls are needed to get this sum) means that either 75 rolls or more than 75 rolls are needed to get this sum = 0.259 + 0.741 = 1

4 0

3 years ago

What is (5a2 − 3a + 8) + (−4a2 − 1) + (15a + 11) expressed in its simplest form?

murzikaleks [220]

The Answer is:

(5a2-3a+8)+(-4a2-1)+(15a+11)

3 0

3 years ago

Read 2 more answers

What is something you learned about in math this week need it for survey

mrs_skeptik [129]

Answer:

we learned very valuble info

Step-by-step explanation:

yes

5 0

2 years ago

Pratap puri rowed 10 miles down a river in 2 hours, but the return trip took him 2 and one half hours. Find the rate pratap can

N76 [4]

Answer:

Rate of Pratap in still water is 4.5 miles/hour and rate of current is 0.5 miles/hour.

Step-by-step explanation:

Pratap Puri rowed 10 miles down a river in 2 hours, but the return trip took him 2.5 hours.

We know that, $Speed = \frac{Distance}{Time}$

So, the speed of Pratap with the current will be: $(\frac{10}{2})miles/hour = 5$ miles/hour

and the speed of Pratap against the current will be: $(\frac{10}{2.5})miles/hour = 4$ miles/hour.

Suppose, the rate of Pratap in still water is $x$ and the rate of current is $y$ .

So, the equations will be........

$x+y= 5 .............................. (1)\\ \\ x-y=4 .............................. (2)$

Adding equation (1) and (2) , we will get......

$2x=9\\ \\ x=\frac{9}{2}= 4.5$

Now, plugging this $x=4.5$ into equation (1), we will get.....

$4.5+y=5\\ \\ y=5-4.5 =0.5$

Thus, Pratap can row at 4.5 miles per hour in still water and the rate of the current is 0.5 miles/hour.

6 0

3 years ago