Question

Find the equationof a circle whose centre is (-3-15) and passing point (5,-1) find the equation of circle..​

Answer 1

Answer: $(x+3)^{2} +(y+15)^{2}=260$

Step-by-step explanation:

The centre is (-3,-15), so we can say the equation of circle is $(x+3)^{2} +(y+15)^{2}=r^{2}$. put (5,-1) at this equation.

then, we can know $r^{2}=260$.

∴ $(x+3)^{2} +(y+15)^{2}=260$