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Lady_Fox [76]
2 years ago
6

Choose the best description of a tessellation.

Mathematics
2 answers:
mixas84 [53]2 years ago
4 0
2.. I think it’s number 2…….. thank me and mark me brainlest
jok3333 [9.3K]2 years ago
3 0

Answer:

I think number 4 I'm not sure

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Helppppp how do u do number 1?
VashaNatasha [74]
Only A
And only when x = 1

Nothing else works.
4 0
2 years ago
Use the quadratic formula to find the solutions to the quadratic equation below 2x^2-5x+5=0
Serggg [28]

Answer:

x = (5 + i sqrt(15))/4 or x = (5 - i sqrt(15))/4

Step-by-step explanation:

Solve for x:

2 x^2 - 5 x + 5 = 0

Hint: | Using the quadratic formula, solve for x.

x = (5 ± sqrt((-5)^2 - 4×2×5))/(2×2) = (5 ± sqrt(25 - 40))/4 = (5 ± sqrt(-15))/4:

x = (5 + sqrt(-15))/4 or x = (5 - sqrt(-15))/4

Hint: | Express sqrt(-15) in terms of i.

sqrt(-15) = sqrt(-1) sqrt(15) = i sqrt(15):

Answer: x = (5 + i sqrt(15))/4 or x = (5 - i sqrt(15))/4

5 0
3 years ago
The car you just bought keeps breaking down. The parts you need to buy cost $408.97. Your mechanic also charges $53 per hour for
DiKsa [7]
C. repair charge = 53 * hours of labor + 408.97
7 0
3 years ago
Read 2 more answers
A basketball is 11 times heavy as a tennis ball. If a tennis ball weighs 58 gram, what is the weight of a basketball in kilogram
Eva8 [605]

Answer:

bout 20 feet

Step-by-step explanation:

5 0
3 years ago
10 points
ollegr [7]

Answer:

FC=25.9

Step-by-step explanation:

<u>Congruent Triangles</u>

The figure shows two triangles FCD and FED. One of their sides is the radius of the circle, they both form a 90° angle with the line CD and ED and they share the same segment FD.

Thus, both triangles are congruent and we have the length of a side (12 units), one common side (the hypotenuse) and one unknown leg that must be equal. Therefore

13x-16=4x+11

Solving

9x=27

x=3

The required side FD is the hypotenuse of any of the triangles. The unknown leg can be calculated by

13x-16=23

Or

4x+11=23

Thus

FD^2=12^2+23^2=673

Solving

FD=\sqrt{673}

\boxed{FC=25.9}

5 0
2 years ago
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