All categories

3 years ago

Today, Joel is going to an art museum to see a special exhibit. It takes Joel 25 minutes to

Mathematics

1 answer:

Marina86 [1]3 years ago

4 0

Answer:

6:55 A. M. is the latest time he can leave his house

You might be interested in

If a musician uses his credit card to pay for a new violin that costs $2,900 and does not pay on it until the second month, what

OLEGan [10]

Answer:

$97.15.

Step-by-step explanation:

We have been given that a musician uses his credit card to pay for a new violin that costs $2,900 and does not pay on it until the second month. The interest rate of credit card is 3.35% monthly.

We will use interest formula to solve our given problem.

$I=PrT$ , where,

$I=\text{Interest}$ ,

$P=\text{Principal amount}$ ,

$r=\text{Interest rate in decimal form}$ ,

$T=\text{Time}$

Let us convert our given interest rate in decimal form.

$3.35\%=\frac{3.35}{100}=0.0335$

Upon substituting our given values in interest formula we will get,

$I=2,900*0.0335*1$

$I=2,900*0.0335$

$I=97.15$

Therefore, the monthly interest charge at the end of the 1st month will be $97.15.

7 0

3 years ago

If the altitude of an isosceles right triangle has a length of x units, what is the length of one leg of the large right triangl

SVETLANKA909090 [29]

the picture in the attached figure

we know that

if ABC is an isosceles triangle

then

AB=BC

angle A=angle C=45 degrees

and

triangle ABD and triangle BDC also are isosceles triangles

AD=BD=x

DC=BD=x

the hypotenuse AC is equal to

$AC=AD+DC\\ AC=x+x\\ AC=2x$

To find the length AB applying the Pythagorean Theorem

$AC^{2} =AB^{2} +BC^{2}$

remember that AB=BC

$AC^{2} =2AB^{2}$

$AC^{2} =2AB^{2}\\\\ AB=\frac{AC}{\sqrt{2}}\\\\ AB=\frac{2x}{\sqrt{2}}\\\\ AB=x\sqrt{2}$

therefore

the answer is

the length of one leg of the large right triangle in terms of x is equal to $x\sqrt{2}$

3 0

4 years ago

Read 2 more answers

How do you determine if an ordered pair is a solution to a system of equations?

Annette [7]

When both lines have that one point that is the same

4 0

3 years ago

When a principal amount, P, is invested at an annual interest rate,r, and compounded n times per

romanna [79]

Answer:

Step-by-step explanation:

A = P( 1+r/n) ^ (nt)

P is the amount invested

r is the rate

n is the number of times per year the interest is compounded

t is the number of years

every 6 months is twice a year

so n is 2

8 0

3 years ago

Read 2 more answers

First verify that y(x)y(x) satisfies the given differential equation. Then determine a value of the constant CC so that y(x)y(x)

zubka84 [21]

Answer:

at constant C = -56 satisfies the given condition of y(x)

Step-by-step explanation:

differentiate y(x) w.r.t.x

$y' (x ) = \frac{d}{dx} (\frac{1}{4} x^5 +Cx^{-3} )$

= $\frac{1}{4}\frac{d}{dx} (x^5) + C\frac{d}{dx} (x^{-3} )$

= $\frac{5}{4} x^4 - 3Cx^{-4}$

attached is the remaining part of the detailed solution and the sketch of the several typical solutions

6 0

3 years ago