The answer to the first part is 3 1/2 and the answer to the second question is 2/7
Answer:
Draw the line segment AB = 7 cm.
Draw ray BX making an acute ∠ABX.
Along BX. mark off five points B1, B2, B3, B4 and B5. Join B2 to A.
Through B5 draw B5P || B2A, intersecting BA produced at P.
The point P so obtained is the required point which divides AB externally in the ratio 3:5.
Answer:
Is there answer choices?
Step-by-step explanation:
Not very clear, could be any number of things. If there are words to choose from i can help you.
Answer:
<h2>(-2, -1)</h2>
Step-by-step explanation:
Convert the inequality to the form y > mx + b:
3x + y > -8 <em>subtract 3x from both sides</em>
y > -3x - 8
Put the coordinates of the points to the inequality and check:
for (-3, 0)
0 > -3(-3) - 8 → 0 > 9 - 8 → 0 > 1 FALSE
for (-2, -1)
-1 > -3(-2) - 8 → -1 > 6 - 8 → -1 > -2 TRUE
for (0, -10)
-10 > -3(0) - 8 → -10 > 0 - 8 → -10 > -8 FALSE
for (2, -16)
-16 > -3(2) - 8 → -16 > -6 - 8 → -16 > -14 FALSE
Answer:
Yes.
Step-by-step explanation:
To see if h is a factor of f, we can use the factor theorem.
h(x)=x-3 has a zero at x=3 because h(3)=3-3=0.
So we want to see if the zero of h is a zero of f.
Is x=3 a zero of f?
You can check using synthetic division or just plug in 3.
Let's do both.
If you use synthetic you are trying to see if you get a remainder of 0.
If you plug it in you are trying to see if you get 0 as the output when plugging your input 3.
Let's do synthetic first:
Since we are checking to see if x=3 is a zero, that will go on the outside:
3 | 1 -1 -1 -15
| 3 6 15
- ------------------------
1 2 5 0
So yep the remainder is 0 so the answer is yes.
Let's plug it in:
f(3)=3^3-3^2-3-15
f(3)=27-9-3-15
f(3)=18-3-15
f(3)=15-15
f(3)=0
The result is 0 so the answer is yes.
You pick your favorite way here.
