Answer:
The length of the flagpole be 41.2 ft .
Option (A) is correct .
Step-by-step explanation:
As given
The angle looking up at the sun is 70°.
A flagpole casts a shadow of 15 ft .
Now by using the trignometric identity .
![tan \theta = \frac{Perpendicular}{Base}](https://tex.z-dn.net/?f=tan%20%5Ctheta%20%3D%20%5Cfrac%7BPerpendicular%7D%7BBase%7D)
![\ theta = 70^{\circ}](https://tex.z-dn.net/?f=%5C%20theta%20%3D%2070%5E%7B%5Ccirc%7D)
![tan\ 70^{\circ} = \frac{AB}{BC}](https://tex.z-dn.net/?f=tan%5C%2070%5E%7B%5Ccirc%7D%20%3D%20%5Cfrac%7BAB%7D%7BBC%7D)
BC = 15 ft
tan 70° = 2.75 (Approx)
![2.75 = \frac{AB}{15}](https://tex.z-dn.net/?f=2.75%20%3D%20%5Cfrac%7BAB%7D%7B15%7D)
AB = 2.75 × 15
= 41.2 ft
Therefore the length of the flagpole be 41.2 ft .
Option (A) is correct .
<span>A foot per second is a unit of speed. Something traveling one foot per second is traveling 0.3048 meters per second, or about 0.682 miles per hour. hope this helped please mark me as the brainliest answer
</span>
9 sq. in because each side is 3 inch and area is length x width. each side is e inch so 3x3=9 sq in.
48 miles/4hrs = 12 mph
Increased Speed 12 mph + 8mph = 20 mph
Distance left 108 miles - 48 miles = 60 miles
Time left 60 miles/20 mph = 3 hours
Since the direction is not specified, it can be safe to assume that the direction of rotation is counterclockwise.
300 degrees is 60 degrees less than 360 degrees, which is a full rotation. Thus, 300 degrees counterclockwise is the same as 60 degrees clockwise.
Note that this shape is a hexagon. Thus, we can divide a hexagon into 6 equilateral triangles, each with measures of 60 degrees. Just move OQ to the adjacent clockwise equilateral triangle and see what it overlaps with.
OQ is the altitude of the equilateral triangle, so our answer will be the altitude of the adjacent clockwise equilateral triangle.
The answer is OF.