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2 years ago

Find the solution of the equation in the interval 0° ≤ x < 360° 1. √3 csc x + 2 = 0

Mathematics

1 answer:

sergejj [24]2 years ago

5 0

Step-by-step explanation:

√3cscx + 2 = 0

cscx = -2/√3

sinx = 1/cscx = -√3/2

We have the basic angle x = 60°.

(Because sin60° = √3/2)

Since sinx is negative, it must fall in Quadrants III or IV.

=> x = 180° + 60° or x = 360° - 60°

=> x = 240° or x = 300°.

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