Find the solution of the equation in the interval 0° ≤ x < 360°
1. √3 csc x + 2 = 0
1 answer:
Step-by-step explanation:
√3cscx + 2 = 0
cscx = -2/√3
sinx = 1/cscx = -√3/2
We have the basic angle x = 60°.
(Because sin60° = √3/2)
Since sinx is negative, it must fall in Quadrants III or IV.
=> x = 180° + 60° or x = 360° - 60°
=> x = 240° or x = 300°.
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