What must occur in order for plants to grow?

Can the segment shown below could form a triangle 658?

bija089 [108]

The segment shown of AC 6 , CB 5, BA 8 can indeed form triangle 658 so this is TRUE.

<h3>How are triangles formed?</h3>

A shape is said to be a triangle when the sum of the lengths of any two sides is greater than the length of the last side.

To prove this, we have:

8 + 6 = 14 which is greater than 5

6 + 5 = 11 which is greater than 8

5 + 8 = 13 which is greater than 6

This shows that the segment can indeed form a triangle 658.

Full question is:

The segment shown below could form a triangle. 6, 5, 8

AC 6 , CB 5, BA 8

Find out more on properties of triangles at brainly.com/question/17228179

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6 0

2 years ago

1.)Why does a parcel of air expand as it rises up in the atmosphere?

Ainat [17]

Answer:

1) option a) is correct.

2) option a) is correct

3) option b) is correct

4) option b) is correct

Explanation:

1) option a) is correct.

as the air rises the pressure decreases.

2) option a) is correct

in completely unsaturated atmosphere sky looks clear.

3) option b) is correct

when a parcel of air that is cooler than the surrounding air at all elevations then is the condition of absolute stability.

4) option b) is correct

During the Bergeron (Ice-crystal process) of precipitation, at the expense of surrounding super cooled liquid ice crystal grow large.

8 0

3 years ago

What is the value of X6? <br><br> Show the solution.

wariber [46]

Answer : The value of $x_6$ is $\sqrt{7}$ .

Explanation :

As we are given 6 right angled triangle in the given figure.

First we have to calculate the value of $x_1$ .

Using Pythagoras theorem in triangle 1 :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(x_1)^2=(1)^2+(1)^2$

$x_1=\sqrt{(1)^2+(1)^2}$

$x_1=\sqrt{2}$

Now we have to calculate the value of $x_2$ .

Using Pythagoras theorem in triangle 2 :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(x_2)^2=(1)^2+(X_1)^2$

$(x_2)^2=(1)^2+(\sqrt{2})^2$

$x_2=\sqrt{(1)^2+(\sqrt{2})^2}$

$x_2=\sqrt{3}$

Now we have to calculate the value of $x_3$ .

Using Pythagoras theorem in triangle 3 :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(x_3)^2=(1)^2+(X_2)^2$

$(x_3)^2=(1)^2+(\sqrt{3})^2$

$x_3=\sqrt{(1)^2+(\sqrt{3})^2}$

$x_3=\sqrt{4}$

Now we have to calculate the value of $x_4$ .

Using Pythagoras theorem in triangle 4 :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(x_4)^2=(1)^2+(X_3)^2$

$(x_4)^2=(1)^2+(\sqrt{4})^2$

$x_4=\sqrt{(1)^2+(\sqrt{4})^2}$

$x_4=\sqrt{5}$

Now we have to calculate the value of $x_5$ .

Using Pythagoras theorem in triangle 5 :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(x_5)^2=(1)^2+(X_4)^2$

$(x_5)^2=(1)^2+(\sqrt{5})^2$

$x_5=\sqrt{(1)^2+(\sqrt{5})^2}$

$x_5=\sqrt{6}$

Now we have to calculate the value of $x_6$ .

Using Pythagoras theorem in triangle 6 :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(x_6)^2=(1)^2+(X_5)^2$

$(x_6)^2=(1)^2+(\sqrt{6})^2$

$x_6=\sqrt{(1)^2+(\sqrt{6})^2}$

$x_6=\sqrt{7}$

Therefore, the value of $x_6$ is $\sqrt{7}$ .

5 0

3 years ago

At which latitude would tropical rain forests be most likely?

horrorfan [7]

Answer:

30 degrees South

Explanation:

rainforests best grow between the Tropic of Cancer (23.5N) and the Tropic of Capricorn (23.5S).

8 0

3 years ago

Fill in the table with the terms that best describe these landforms.

Ipatiy [6.2K]

Answer:

Landforms are the physical features on the Earth's surface. Mountains, Plateaus and Plains are some major landforms of the Earth

Explanation:

3 0

3 years ago