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3 years ago

6

You can answer any of these, just make sure to put the number (1., 2. Etc) of which ever one you answered (try to answer as much

as you can!)

2 answers:

Dmitry [639]3 years ago

8 0

Answer: number three is c. Not 100% positive, but I’m pretty sure

Step-by-step explanation:

harina [27]3 years ago

3 0

I do t know the answer but I need to get more point so I can get more answers for my test
Have a bless day

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A classroom is arranged with 8 seats in the front row, 10 seats in the middle row, and 12 seats in the back row. The teacher ran

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1/20

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4 years ago

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F(x) = x<br> Horizontal stretch by a factor of 2<br> Shift left 3 units<br> . Shift up 5 units

WARRIOR [948]

Answer:

f(x) = 0.5(x + 3)^2 + 5.

Step-by-step explanation:

The horizontal stretch is given by multiplying by 1/2 or 0.5:

f(x) = 0.5x^2

Now a shift of 3 to the left gives f(x) = 0.5(x + 3)^2.

5 units up gives 0.5(x + 3)^2 + 5.

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4 years ago

A local hospital tracked the blood type and gender of the patients they saw one day. Which is a fair statement?

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4 years ago

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Test the claim that the proportion of men who own cats is smaller than the proportion of women who own cats at the .10 significa

nata0808 [166]

Answer:

The test statistics is $t = -1.40$

The critical value is $Z_{\alpha } = 2.33$

The null hypothesis is rejected

Step-by-step explanation:

From the question we are told that

The sample size for men is $n_1 = 80$

The sample proportion of men that own a cat is $\r p _M = 0.40$

The sample size for women is $n_2 = 80$

The sample proportion of women that own a cat is $\r p_F = 0.51$

The level of significance is $\alpha = 0.10$

The null hypothesis is $H_o : \r p _M = \ r P_F$

The alternative hypothesis is $H_a : \r p _M < \r p_F$

Generally the test statistic is mathematically represented as

$t = \frac{(\r p_M - \r p_F)}{\sqrt{\frac{(p_M*(1-p_M)}{n_1 } } + \frac{p_F*(1-pF)}{n_2 } }$

=> $t = \frac{(0.40 - 0.51)}{\sqrt{\frac{(0.40 *(1-0.41)}{80} } + \frac{0.51*(1-0.51)}{80 } }$

=> $t = -1.40$

The critical value of $\alpha$ from the normal distribution table is

$Z_{\alpha } = 2.33$

The p-value is obtained from the z-table ,the value is

$p-value = P( Z < -1.40) = 0.080757$

=> $p-value = 0.080757$

Given that the $p-value < \alpha$ then we reject the null hypothesis

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3 years ago

Mike kohl, an employee of spotswood company, has gross earnings for the month of october of $8,000. fica taxes are 7.65% of gros

boyakko [2]

Gross earning = $8,000
FICA tax = 8000*0.0765 = $612
Federal income tax = $1,270
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Net pay = 8000-2062 = $5,938

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3 years ago