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2 years ago

Mr downs bought a camera for 56$. this was 80% of the list price. what was the list price

Mathematics

1 answer:

Vsevolod [243]2 years ago

5 0

I got 70 as the list price. If it’s multiple choice and 70 isn’t one of the answers I’m sorry

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What is the equation of the line that passes<br> through the points (3, 3) and (5, -9)?

sineoko [7]

Answer:

y=3x-15

Step-by-step explanation:

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3 years ago

Factor completely 3bx2 − 9x3 − b + 3x. (b − 3x)(3x2 − 1) (b + 3x)(3x2 + 1) (b + 3x)(3x2 − 1) Prime

Daniel [21]

$3bx^2-9x^3-b+3x=\boxed{3x^2}\cdot b-\boxed{3x^2}\cdot3x\fbox{-1}\cdot b\fbox{-1}\cdot (-3x)\\\\=\boxed{3x^2}(b-3x)\fbox{-1}(b-3x)=\boxed{(b-3x)(3x^2-1)}\\\\completely:\\use:a^2-b^2=(a-b)(a+b)\to3x^2-1=(x\sqrt3)^2-1^2=(x\sqrt3-1)(x\sqrt3+1)$
$therefore:\\3bx^2-9x^3-b+3x=(b-3x)(3x^2-1)\\=\underline{\underline{(b-3x)(x\sqrt3-1)(x\sqrt3+1)}}$

6 0

3 years ago

Read 2 more answers

Which binomial is a difference of squares?

GenaCL600 [577]

D) 36x^2-81
both 36x^2 and -81 are perfect squares
difference means subtraction

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3 years ago

X = ? y = ? 16 45 degrees

mezya [45]

Let's put more details in the figure to better understand the problem:

Let's first recall the three main trigonometric functions:

$\text{ Sine }\theta\text{ = }\frac{\text{ Opposite Side}}{\text{ Hypotenuse}}$ $\text{ Cosine }\theta\text{ = }\frac{\text{ Adjacent Side}}{\text{ Hypotenuse}}$ $\text{ Tangent }\theta\text{ = }\frac{\text{ Opposite Side}}{\text{ Adjacent Side}}$

For x, we will be using the Cosine Function:

$\text{ Cosine }\theta\text{ = }\frac{\text{ Adjacent Side}}{\text{ Hypotenuse}}$ $Cosine(45^{\circ})\text{ = }\frac{\text{ x}}{\text{ 1}6}$ $(16)Cosine(45^{\circ})\text{ = x}$ $(16)(\frac{1}{\sqrt[]{2}})\text{ = x}$ $\text{ }\frac{16}{\sqrt[]{2}}\text{ x }\frac{\sqrt[]{2}}{\sqrt[]{2}}\text{ = }\frac{16\sqrt[]{2}}{2}$ $\text{ 8}\sqrt[]{2}\text{ = x}$

Therefore, x = 8√2.

For y, we will be using the Sine Function.

$\text{ Sine }\theta\text{ = }\frac{\text{ Opposite Side}}{\text{ Hypotenuse}}$ $\text{ Sine }(45^{\circ})\text{ = }\frac{\text{ y}}{\text{ 1}6}$ $\text{ (16)Sine }(45^{\circ})\text{ = y}$ $\text{ (16)(}\frac{1}{\sqrt[]{2}})\text{ = y}$ $\text{ }\frac{16}{\sqrt[]{2}}\text{ x }\frac{\sqrt[]{2}}{\sqrt[]{2}}\text{ = }\frac{16\sqrt[]{2}}{2}$ $\text{ 8}\sqrt[]{2}\text{ = y}$

Therefore, y = 8√2.

5 0

1 year ago

HELP ASAP PLEAse!!! HOW DO YOU FIND THE LATERAL AREA OF THE TRIANGLE, (ALREADY GOT SURFACE AREA CORRECT), PLEASE ROUND IT TO THE

Zarrin [17]

172.9

You find it by multiplying each side of the triangle by the height (9) and adding the results together.

A(lateral) = 8 * 9.1 + 3 * 9.1 + 8 * 9.1
= 72.8 + 27.3 + 72.8
= 172.9

6 0

2 years ago