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FromTheMoon [43]

2 years ago

14

Can you prove these similar triangle step by step?

1 answer:

RUDIKE [14]2 years ago

4 0

Answer:

If an angle of one triangle is congruent to the corresponding angle of another triangle and the lengths of the sides including these angles are in proportion, the triangles are similar. the remaining sets of angles will be congruent and the remaining corresponding sides will be in proportion.

hopes this helps

Step-by-step explanation:

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1 year ago

Write the following expression with as few symbols as possible, using the notational conventions:

My name is Ann [436]

Answer:

The simplified expressions are (<em>x</em> + <em>y·</em>z' + <em>t</em>) and <em>x·</em>(<em>x</em> + <em>y</em>' + <em>z</em>) respectively.

Step-by-step explanation:

The expressions provided are:

$(i)\ x+((y\times (z')) +t)\\\\(ii)\ x\times((x+(y'))+z)$

(i)

Simplify the first expression with as few symbols as possible:

$x+((y\times (z')) +t)=x+(yz'+t)$

$=x+yz'+t$

(ii)

Simplify the second expression with as few symbols as possible:

$x\times((x+(y'))+z)=x\times ((x+y')+z)$

$=x (x+y'+z)$

Thus, the simplified expressions are (<em>x</em> + <em>y·</em>z' + <em>t</em>) and <em>x·</em>(<em>x</em> + <em>y</em>' + <em>z</em>) respectively.

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3 years ago