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Anarel [89]
3 years ago
9

Solve for X. A. 168 B. 180 C. 21 D. 42

Mathematics
1 answer:
Korvikt [17]3 years ago
4 0

Answer:

Answer = C

Angle x = 21

Property = Angle sum of Triangle

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Brainliest points whatever you want please
nadya68 [22]

Annual rate of return earned when the share was sold at $50 per share is 20%

Annual rate of return earned when the share was sold at $60 per share is 40%

<h3>How to calculate annual rate of return</h3>

Annual rate of return is given by the formula

let end of the year price = eyp

let beginning of the year price = byp

= {(eyp - byp) / byp} * 100

Annual rate of return at share price of $50 per share

when there is paying of dividends the value is added to the the eyp

eyp =  50 * 100 + 2 * 100 * 5 = 6000

byp = 50 * 100 = 5000

= {(6000 - 5000) / 5000} * 100

= 20%

Annual rate of return at share price of $60 per share

eyp =  60 * 100 + 2 * 100 * 5 = 7000

byp = 50 * 100 = 5000

= {(7000 - 5000) / 5000} * 100

= 40%

Learn more about annual rate of return here:

brainly.com/question/3578105

#SPJ1

4 0
1 year ago
there were 632 animals gathered at the river. a herd of 187 elephants and 266 zebras left the river area. how many animals were
Simora [160]

Answer: There was a total of 173 animals left by the river

Step-by-step explanation:187+266 = 453

You subtract 453 from the total number of animals which is 632

632-453 = 179

6 0
3 years ago
Whats 521,742 rounded to the nearest thousand
n200080 [17]
The answer is 521 000
4 0
3 years ago
Read 2 more answers
What is the amplitude, period, and phase shift of y= 5cos( x/2 + 2pi/3)
nordsb [41]
Y = A cos(Bx + C)
A - amplitude
\frac{2\pi}{B} - period
- \frac{C}{B} - phase shift

y=5\cos{( \frac{x}{2} + \frac{2\pi}{3} )}&#10;\\&#10;\\y=5\cos{( \frac{1}{2}x + \frac{2\pi}{3})}&#10;\\&#10;\\A=5,B= \frac{1}{2},C= \frac{2\pi}{3}

Amplitude: 5
Period: \frac{2\pi}{B}=\frac{2\pi}{\frac{1}{2}}=4\pi
Phase shift: - \frac{C}{B} =- \frac{\frac{2\pi}{3}}{\frac{1}{2}}= -\frac{4\pi}{3}
3 0
3 years ago
Four int variables, x1, x2, y1, and y2, have been declared and been given values. write an expression whose value is the differe
Katen [24]
Even though we are using variables, we still know that "difference" means subtraction. So, if the larger is x1 and x2, those variables go first. The smaller, y1 and y2 will go second. So our problem will look like this:

(x1 <  x2 ? x2 : x1) - (y1 < y2 ? y1 : y2)
7 0
3 years ago
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