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3 years ago

15

Want money answer this.

2 answers:

jok3333 [9.3K]3 years ago

8 0

Answer: CM:ME (6.71:4.47) = 1.5 : 1

Step-by-step explanation:

the coordinates of the endpoints of CE are C(-3, -7) and E(7, -2). point M (3, -4) is on CE. What is the ratio of CM:ME? This is a distance formula problem, where you are comparing the two ratio's of CM to ME.

It is well worth your time to memorize the distance formula: d = sqrt ((x - x1)2 + (y - y1)2) using two points: (x,y), (x1,y1). You will use this many, many times in your math classes.

CM: sqrt ((-3 - 3)2 + (-7 - -4)2) = sqrt ((6)2 + (-3)2) = sqrt (45) ≅ 6.71

ME: sqrt ((3 - 7)2 + (-4 - -2)2) = sqrt ((-4)2 + (-2)2) = sqrt (20) ≅ 4.47

CM:ME (6.71:4.47) = 1.5 : 1

Lorico [155]3 years ago

6 0

Answer:

Is this a scam

Step-by-step explanation:

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Answer:

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3 0

3 years ago

What is the average rate of change for h(t) between t=0 and t=2

nordsb [41]

Part a: Option D 18 feet per second

Part b: increasing

Solution:

Height $h(t)=-16 t^{2}+50 t+3$

Part a: To find the average rate of change for h(t) between t = 0 and t = 2.

Substitute t = 0 in h(t).

$h(0)=-16 (0)^{2}+50 (0)+3$

h(0) = 3

Substitute t = 2 in h(t).

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h(2) = 39

Average rate of change formula:

$$=\frac{h(b)-h(a)}{b-a}$

Here, a = 0 and b = 2.

$$=\frac{h(2)-h(0)}{2-0}$

$$=\frac{39-3}{2}$

$$=\frac{36}{2}$

= 18

Average rate of change = 18 feet per second

Option D is the correct answer.

Part b:

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3 years ago

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3 years ago

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aleksandr82 [10.1K]

Example:
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3 years ago

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Answer:

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3 years ago