Answer:
C. Byte pair encoding is an example of a lossless transformation because an encoded string can be restored to its original version.
Explanation:
Byte pair encoding is a form of encoding in which the most common pairs of consecutive bytes of data are replaced by a single byte which does not occur within the set of data.
For example, if we has a string ZZaaAb, it can be encoded if the pairs of string ZZ are replaced by X and the second pair by Y. So, our data now becomes XYAb.
To get our original data, that is decode it, we just replace the data with the keys X = ZZ and Y = aa thus allowing our original data to be restored.
Since our original string is restored without loss of data, it implies that <u>byte pair encoding is an example of a lossless transformation because an encoded string can be restored to its original version.</u>
The procedure is known as<u> context switching</u>.
In the field of computers, context switching can be described as a procedure in which a process is stored so that it can be executed at a later point. Such a procedure allows multitasking operations easier. A simple CPU can be utilized for multiple processes.
After a task is done, it can be swapped out of the CPU and can be restored later. By using context switching, more space can be provided on a CPU as freeing from one process will make space for the other.
When switching a process, the status of the older running process is saved on the CPU as registers.
Context switch makes it feasible to share one CPU for multiple procedures hence reducing the concerns that arise from using additional processors.
To learn more about context switch, click here,
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Answer:
Person-to-Group
Explanation:
Person-to-Group communication involves one speaker and audience.
Answer:
Using python programming language.
Explanation:
#to define the function write as below
def equal():
#to get the two integers from the user
#The user is asked for input in the code below.
x = int(input("Enter the value for X"))
y= int(input("Enter the value for y"))
if x==0 and y==0:
print("both numbers are ", "0")
elif: x==1 and y==1: #This test if both x and y are 1
print("true")
elif: x==y: #this line test if both values are equal
print("true")
else:
print("False")
equal() #end of the function
Answer:
Explanation:
The following code is written in Java and is a function/method that takes in an int array as a parameter. The type of array can be changed. The function then creates a counter and loops through each element in the array comparing each one, whenever one element is found to be a duplicate it increases the counter by 1 and moves on to the next element in the array. Finally, it prints out the number of duplicates.
public static int countDuplicate (int[] arr) {
int count = 0;
for(int i = 0; i < arr.length; i++) {
for(int j = i + 1; j < arr.length; j++) {
if(arr[i] == arr[j])
count++;
}
}
return count;
}
