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container B needs to be filled faster in order for both containers to gain the same amount of water per minute , and by 1/6 water per minute .
<u>Step-by-step explanation:</u>
Here we have , two leaky containers are filling with water. water enters container a at a rate of 2/3 cup per 1/2 minute and leaks out at a rate of 1/4 cup per 3/4 minute. water enters container b at a rate of 3/4 cup per 1/2 minute and leaks out at a rate of 1/2 cup per 3/4 minute. We need to find which container needs to be filled faster in order for both containers to gain the same amount of water per minute . Let's find out:
Rate of Filling container A:
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Rate of leaking Container A:
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Amount of water in Container A in one minute :
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No , following same for Container B
Rate of Filling container B:
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⇒
Rate of leaking Container B:
⇒
⇒
Amount of water in Container B in one minute :
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Since , Rate of water per minute in container A is 1 and , Rate of water per minute in container B is 5/6 , container A fills faster by container B by
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Therefore , container B needs to be filled faster in order for both containers to gain the same amount of water per minute , and by 1/6 water per minute .
Answer:
see below
Step-by-step explanation:
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If you need to find points on the curve, you can substitute x=0, 1, 2, 3 into the function to see what they are. For example, f(0) = 0²-3 = -3; f(1) = 1² -3 = -2; and so on. The curve is symmetrical about the y-axis, so the points on the left are mirror images of the points on the right.
