Answer:
the question is not finished amigo
Answer:
Remove and lower.
Explanation:
Cells of the excretory tubule remove water by osmosis, from which we can conclude that the solute concentration in these cells must be lower than in the filtrate. The excretory tubule remove excess amount of water from the cell through semi permeable membrane of the cell while on the other hand, the solute concentration in the cell is lower as compared to filtrate so that's why it can't diffuse from the cell by the process of osmosis.
Answer:
C) Prevent chromosome from separating.
Explanation:
Cytoskeletons can be called as movers and shapers of the cell. It is protein filament in the cell or the inter cellular proteins. The smallest part of a cytoskeleton is microfilament (7nm). Cytoskeletons control the interior workups of a cell. Cytoskeletons extended through cytoplasm.
all membrane bound organelles are absent in prokaryotic cells. They only have a membrane, cytoplasm, DNA and ribosomes(and also some sort of a cytoskeleton that helps with division and cell shape)
Hope this helps
<h2><u>
Full Question:</u></h2>
In the family tree below, people with the recessive trait of attached earlobes are shaded gray.
What must be true about the person labeled "A"?
A. It is a male with at least one dominant allele.
B. It is a male with two dominant alleles.
C. It is a female with at least one dominant allele.
D. It is a female with two dominant alleles.
<h2><u>Answer:</u></h2>
Its a male with atleast one dominant allele.
Option A.
<h3><u>Explanation:</u></h3>
The gene for the attached earlobe is recessive while the gene for the free earlobes is dominant. In the phylogenetic tree, we can see that both the father and mother aren't having attached earlobes. So both of them are having atleast one dominant allele which makes them have free earlobe.
In the F1 offsprings, one of the female and a male is having free earlobes. So both of them have atleast one dominant allele. The 2nd female is having an attached earlobe. So both the recessive allele have come form one parent each. So both of them are heterozygous.
Thus, the male marked as A atleast have one dominant allele. He can be a homozygous dominant, but the probability is 25%.