Please help....And please show steps..

What is 0.9 written as a decimal

arsen [322]

It is already in a decimal

I think you mean percent, so it will be 90%

Sorry if that is not what you mean

6 0

2 years ago

Read 2 more answers

A 4000 kg truck is parked on a 7.0° slope. How big is the friction force on the truck?

Lelu [443]

Answer:

4777.28 N

Step-by-step explanation:

The gravitational force down the slope is given by the formula;

(mass *g * sin θ )

where;

θ is the angle of inclination of the slope

g is the gravitational pull

We plug in the given values into the above expression;

(4,000 x 9.8 x sin 7) = 4777.28 N.

The frictional force must equal to 4777.28 N (pointing up the slope).

5 0

2 years ago

Find the length of the segment with endpoint Y(4, 3) and midpoint M(1, 7).

inessss [21]

Answer:the length is 10

Step-by-step explanation:

since m is the midpoint it is 3 away from y on the x axis and 4 away on the y axis

so if you go the same distance away from the midpoint you get -2, 11

so -2 is 6 away from 4 away and 3 is 8 away from 11

6^2 = 36

8^2 = 64

36+64= 100

the square root of 100 is 10

5 0

3 years ago

Umm whats y2 when y is -9 and whats z2 when z is 0.7 im not that smart so ill be asking alot

Dmitry_Shevchenko [17]

Answer:

Step-by-step explanation:

y = - 9

y^2 = (-9)^2 = 81

AND

z = 0.7

z^2 = (0.7)^2 = 0.49

Hope it helped

6 0

2 years ago

"6. A brand name has a 40% recognition rate. Assume the owner of the brand wants to verify that rate by beginning with a small s

statuscvo [17]

Answer:

(a) The probability that exactly 5 of the 6 consumers recognize the brand name is 0.0369.

(b) The probability that all of the selected consumers recognize the brand name is 0.0041.

(c) The probability that at least 5 of the selected consumers recognize the brand name is 0.041.

(d) The events of 5 customers recognizing the brand name is unusual.

Step-by-step explanation:

Let X = number of consumer's who recognize the brand.

The probability of the random variable X is, P (X) = p = 0.40.

A random sample of size, n = 6 consumers are selected.

The random variable X follows a Binomial distribution with parameters n and p.

The probability mass function of X is:

$P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...$

(a)

Compute the value of P (X = 5) as follows:

$P(X=5)={6\choose 5}0.40^{5}(1-0.40)^{6-5}\\=6\times0.01024\times0.60\\=0.036864\\\approx0.0369$

Thus, the probability that exactly 5 of the 6 consumers recognize the brand name is 0.0369.

(b)

Compute the value of P (X = 6) as follows:

$P(X=6)={6\choose 6}0.40^{6}(1-0.40)^{6-6}\\=1\times 0.004096\times1\\=0.004096\\\approx0.0041$

Thus, the probability that all of the selected consumers recognize the brand name is 0.0041.

(c)

Compute the value of P (X ≥ 5) as follows:

P (X ≥ 5) = P (X = 5) + P (X = 6)

= 0.0369 + 0.0041

= 0.041

Thus, the probability that at least 5 of the selected consumers recognize the brand name is 0.041.

(d)

An event is considered unusual if the probability of its occurrence is less than 0.05.

The probability of 5 customers recognizing the brand name is 0.0369.

This probability value is less than 0.05.

Thus, the events of 5 customers recognizing the brand name is unusual.

8 0

3 years ago