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Firlakuza [10]
3 years ago
5

Find the length of the leg x

Mathematics
2 answers:
Iteru [2.4K]3 years ago
6 0

Answer:

15.23

Step-by-step explanation:

That is the missing side.

To find the answer, we need the Pythagorean theorem.

a^2 + b^2 = c^2

Let c be the missing side:

c = a2 + b2 = 142 + 62 ≈ 15.23155

C is equal to 15.23155

shutvik [7]3 years ago
5 0

Answer:

12.65

Step-by-step explanation:

Pythagoras :

c² = a² + b²

c is the Hypotenuse (the side opposite of the 90 degree angle).

a and b are the side legs.

so, here we have

14² = 6² + b²

196 = 36 + b²

160 = b²

b = sqrt(160) = sqrt(16×10) = 4×sqrt(10) = 12.65

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Select the correct answer.
Nina [5.8K]

Answer:

D. x^2 + 3x - 88

Step-by-step explanation:

Area of rectangle = length (l) * width (w)

Length of rectangle = (x - 8)

Width = (x + 11)

Area of rectangle = (x - 8)(x + 11)

Expand the expression

x(x + 11) -8(x + 11) (distributive property of multiplication)

x^2 + 11x - 8x - 88

Combine like terms

x^2 + 3x - 88

Expression for the area of the rectangle = x^2 + 3x - 88

7 0
3 years ago
SOLVED
Nastasia [14]
5)
a. The equation that describes the forces which act in the x-direction: 
<span>     Fx = 200 * cos 30 </span>
<span>
b. The equation which describes the forces which act in the y-direction: </span>
<span>     Fy = 200 * sin 30 </span>

<span>c. The x and y components of the force of tension: </span>
<span>    Tx = Fx = 200 * cos 30  </span>
<span>    Ty = Fy = 200 * sin 30 </span>

d.<span>Since desk does not budge, </span><span>frictional force = Fx
                                                                        = 200 * cos 30 </span>

<span>                                                 Normal force </span><span>= 50 * g - Fy
                                                                       = 50 g - 200 * sin 30 
</span>____________________________________________________________
6)<span> Let F_net = 0</span>
a. The equation that describes the forces which act in the x-direction: 
    (200N)cos(30) - F_s = 0

b. The equation that describes the forces which act in the y-direction:
    F_N - (200N)sin(30) - mg = 0

c. The values of friction and normal forces will be:
     Friction force= (200N)cos(30),
     
The Normal force is not 490N in either case...
Case 1 (pulling up)
F_N = mg - (200N)sin(30) = 50g - 100N = 390N

Case 2 (pushing down)
F_N = mg + (200N)sin(30) = 50g + 100N = 590N
4 0
4 years ago
Hello help me with this question thanks in advance​
AfilCa [17]
<h2>Question #22 Answer</h2>

B. 2 in.

<h3>Explanation:</h3>

\frac{3\times4}{6}

Cross out the common factor

\frac{4}{2}\\ 2

________________________________________________________

<h2>Question #23 Answer (Picture attached)</h2>

D. proportional, equal

<h3>Explanation:</h3>

Two\ figure\ are\ sand\ to\ \\ be\ similar\ if\ the\\ Conesesponding\ sides\ we\\ proportional\ and\ the\\ Corresponding\ ongles\ are\\ equal.

If\ triangle\ ΔABC\ is\ similar\ to
Δ × yz.\ Thes
\frac{AB}{xy}=\frac{AC}{xz}=\frac{BC}{yz}

and

< A= < X,\ < B= < y\ and\ < C= < z

5 0
3 years ago
A. When x = -1, what is the value of y?
pogonyaev

Answer:

i think we need more context to this answer.  I’d love to help no need to retype. You can just message me for help :)

Step-by-step explanation:

7 0
3 years ago
On a horizontal number line, numbers to the...... are less than numbers to the..... Numbers to the right are........ numbers to
Neko [114]

on a horizontal number line . numbers to the left are less than numbers to the right .. numbers to the right are less than numbers to the left

8 0
3 years ago
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