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KATRIN_1 [288]
3 years ago
12

In ΔBCD, the measure of ∠D=90°, the measure of ∠B=71°, and DB = 67 feet. Find the length of BC to the nearest tenth of a foot.

Mathematics
2 answers:
Paladinen [302]3 years ago
6 0

Answer:  Side BC would be 205.7ft

Step-by-step explanation:

lora16 [44]3 years ago
6 0

Answer:

in triangle BCD

relationship between base and hypotenuse is given by cos angle

cos 71=b/h

cos71=BD/BC

cos71=67/x

x=67/cos71=205.8ft.

the length of BC to the nearest tenth of a foot is 206ft.

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