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3 years ago

What mistake was made? Please help!

Mathematics

1 answer:

Goryan [66]3 years ago

7 0

Answer:

soooooo basically,

Step-by-step explanation:

10x-1 DOES NOT equal 59

the angels are very different

we will say the line intersecting m and n makes it where 59 and the angel next to it must equal 180

so find that angel

180-59=121

therefore it should be

10x-1+59=180

combine like terms

10x+58=180

subtract 58 from BOTH sides

which cancels 58 on the LEFT side

10x=122

divide 10 from BOTH sides

which cancels the 10 on the LEFT side

which is leaving us with

x=12.2

x=61/5

hope i helped

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2. A square is divided into smaller squares and

Oduvanchick [21]

Answer:

1.5 ft^2

Step-by-step explanation:

Since the length is divided into 4 parts,

Length of a small square = 2/4

= 0.5 ft

Hence,

Area of 1 small square = (0.5)(0.5)

= 0.25 ft^2

Area of shaded portion = Area of 6 small squares

= 6(0.25)

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4 0

3 years ago

Read 2 more answers

A quality control expert at LIFE batteries wants to test their new batteries. The design engineer claims they have a variance of

iris [78.8K]

Answer:

The probability that the mean battery life would be greater than 533.2 minutes (in a sample of 75 batteries) is $\\ P(z>0.48) = P(x>533.2) = 0.3156$

Step-by-step explanation:

The main thing we have to take into account in this question is that we are about to find the probability of a sample mean. The distribution for sample means follows a normal distribution with mean $\\ \mu$ and standard deviation $\\ \frac{\sigma}{\sqrt{n}}$ . Mathematically

$\\ \overline{x} \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

For values of the sample $\\ n \ge 30$ , no matter the distribution the data come from.

And the variable z follows a standard normal distribution, and, as we can remember, this distribution has a mean = 0 and a standard deviation = 1. Mathematically

$\\ z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}$ [1]

That is

$\\ z \sim N(0, 1)$

We have a variance of 3364. That is, a standard deviation of

$\\ \sigma^2 = 3364; \sigma = \sqrt{3364} = 58$

The population mean is

$\\ \mu = 530$

The sample size is $\\ n = 75$

The sample mean is $\\ \overline{x} = 533.2$

With all this information, we can solve the question

The probability that the mean battery life would be greater than 533.2 minutes

Using equation [1]

$\\ z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}$

$\\ z = \frac{533.2 - 530}{\frac{58}{\sqrt{75}}}$

$\\ z = \frac{3.2}{\frac{58}{8.66025}}$

$\\ z = \frac{3.2}{6.69726}$

$\\ z = 0.47780$

With this value of z we can consult a cumulative standard normal table (or use some statistic program) to find the cumulative probability for z (and remember that this variable follows a standard normal distribution).

Most standard normal tables have values for z for only two decimals, so we can round the previous value for z as z = 0.48.

Then

$\\ P(z$

However, in the question we are asked for $\\ P(z>0.48) = P(x>533.2)$ . As well as all normal distributions, the standard normal distribution is symmetrical around the mean, and we have

$\\ P(z>0.48) = 1 - P(z$

Thus

$\\ P(z>0.48) = 1 - 0.68439$

$\\ P(z>0.48) = 0.31561$

Rounding to four decimal places, we have

$\\ P(z>0.48) = 0.3156$

So, the probability that the mean battery life would be greater than 533.2 minutes is (in a sample of 75 batteries) $\\ P(z>0.48) = P(x>533.2) = 0.3156$ .

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4 years ago

Write a compound interest function to model the following situation. Then, find the balance after the given number of years. $16

VARVARA [1.3K]

Answer:

Step-by-step explanation:b

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3 years ago

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Jess gave her nail technician a $4.90 tip. The tip was 14% of the cost of the manicure. Write an equation to find b, the cost

jonny [76]

Answer:

$35

Step-by-step explanation:

equation to represent the situation:

4.90 = 0.14 * b

so,

4.90 / 0.14 = b

b = 35

The cost of the manicure was $35.

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3 years ago

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damaskus [11]

Here’s the correct answer, how I got it, and something to help you for next time. I know it’s a lot of words but if u read the explanation it might help you :)

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