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Ann [662]
3 years ago
10

A(0,6) and B(10,0) are two point and O is the origin. find the equation of the median OM and altitude OD of triangle AOB​

Mathematics
1 answer:
aleksandrvk [35]3 years ago
6 0

Answer:

jriridtigcotjtsdhydkutxitddykkgfyiftjddyk

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Solve for y<br> x+y= -15
Illusion [34]

X + y = -15. Subtract x from both sides.

y = -x - 15. This is as far as we can go with the provided information.

5 0
3 years ago
Read 2 more answers
What is the value of x<br> What is the value of the exterior angle
Oduvanchick [21]

Answer:

???????

Step-by-step explanation:

triangles add to 180 degrees

lets call the unknown angle y

82 + x + y = 180

we also know that y + (2x-20 ) = 180  because it is a straight line

lets solve this for y

y + (2x-20 ) = 180

subtract (2x-20) from each side

y = 180 - (2x-20)

y = 180 - 2x + 20

y = 200 -2x

substitute this in the triangle equation

82 + x + y = 180

82 + x + 200 -2x = 180

combine like terms

282 -x = 180

subtract 282 from each side

-x = -102

multiply by -1 on each side

x = 102

the exterior angle is 2x-20

exterior angle is 2(102) -20

exterior angle is 204-20

exterior angle is 184

This is impossible.


There is a mistake with this problem

The triangle is not a triangle.  Angle y would be negative. y=-4

6 0
3 years ago
Given f(x)=-2/3x+3 and g(x)=-2x^2-5
timama [110]

Answer:

2/3 give 3 with a g(8) 25 real

3 0
3 years ago
Pls help
KATRIN_1 [288]

Answer:

169.04 in² (nearest hundredth)

Step-by-step explanation:

Surface area of a cone = \pir² + \pirl

(where r = radius of the base and l = slant height)

Given slant height l = 10 and surface area = 188.5

Surface area  = \pir² + \pirl

188.5 = \pir² + 10\pir

\pir² + 10\pir - 188.5 = 0

r = \frac{-10\pi +\sqrt{(10\pi )^2-(4\times\pi \times-188.5)} }{2\pi } = 4.219621117...

Volume of a cone = (1/3)\pir²h

(where r = radius of the base and h = height)

We need to find an expression for h in terms of l using Pythagoras' Theorem a² + b² = c², where a = radius, b = height and c = slant height

r² + h² = l²

h² = l² - r²

h = √(l² - r²)

Therefore, substituting found expression for h:

volume of a cone = (1/3)\pir²√(l² - r²)

Given slant height l = 10 and r = 4.219621117...

volume = 169.0431969... = 169.04 in² (nearest hundredth)

5 0
3 years ago
Read 2 more answers
1. A circle with center (-5, 2) is tangent to the y-axis. What is the radius of the circle? What is the equation of the circle?
Bess [88]

Answer:

Step-by-step explanation:

1)  The center lies on the vertical line x = -5 and the the circle is tangent to (touches in one place only) the y-axis.  Thus, the radius is 5.

2)  Starting with (x - h)^2 + (y - k)^2 = r^2 and comparing this to the given

                     (x - 4)^2 + (y + 3)^2 = 6^2

we see that h = 4, k = -3 and r = 6.  The center is at (4, -3) and the radius is 6.

3)  Notice that A and B have the same x-coordinate, x = 15.  The center of the circle is thus (15, -2), where that -2 is the halfway point between the two given points in the vertical direction.   Arbitrarily choose A(15, 4) as one point on the circle.  Then the equation of this circle is

(x - 4)^2 + (y + 3)^2 = r^2 = 6^2, where the 6 is one half of the vertical distance between A(15, 4) and B(15, -8) (which is 12).

4 0
3 years ago
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