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From my research, the image below belongs to the question. From what is seen in the image, there are 2 arcs already drawn with respect to the new vertex. The third arc corresponds to the point where the line DM is made. This line is similar to line BC. So at the point where the second and third arcs would meet, it would be a point similar to a point on line AB.
The second degree polynomial with leading coefficient of -2 and root 4 with multiplicity of 2 is:
<h3>How to write the polynomial?</h3>
A polynomial of degree N, with the N roots {x₁, ..., xₙ} and a leading coefficient a is written as:
Here we know that the degree is 2, the only root is 4 (with a multiplicity of 2, this is equivalent to say that we have two roots at x = 4) and a leading coefficient equal to -2.
Then this polynomial is equal to:
If you want to learn more about polynomials:
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Answer:
In triangle SHD and triangle STD.
[Side]
Since, a line is said to be perpendicular to another line if the two lines intersect at a right angle.
⇒
[leg] [Given]
Reflexive property states that the value is equal to itself.
[Leg] [Reflexive property]
HL(Hypotenuse-leg) theorem states that any two right triangles that have a congruent hypotenuse and a corresponding congruent leg are the congruent triangles.
then, by HL theorem;
Proved!
