How many solutions does this system have?
1 answer:
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Solution/Answer : 4
Solution: the first you do is multiply the last two parentheses to get -10xy
Now we are left with ( -2/5x)(-10xy)
Then we multiply that out into
(-2*-10)/5*x^2y = 20/5x^2y =
4x^2y
The coefficient in this case would be four. (In case you were confused about what a coefficient actually is, it’s the number you multiply a variable by)
Hopes this helps :)
Solution: the first you do is multiply the last two parentheses to get -10xy
Now we are left with ( -2/5x)(-10xy)
Then we multiply that out into
(-2*-10)/5*x^2y = 20/5x^2y =
4x^2y
The coefficient in this case would be four. (In case you were confused about what a coefficient actually is, it’s the number you multiply a variable by)
Hopes this helps :)
Answer:
Step-by-step explanation:
Joint variation problem solve using the equation y = kxz.
e ∝ fg
e=kfg
now substitute the values
The relationship will be: