All categories

3 years ago

Market Targeting là gì ?

SAT

1 answer:

uysha [10]3 years ago

5 0

Answer:

Market targeting is a process of selecting the target market from the entire market. Target market consists of group/groups of buyers to whom the company wants to satisfy or for whom product is manufactured, price is set, promotion efforts are made, and distribution network is prepared.

You might be interested in

An angle that measures from the horizontal upward to an object is called the angle of

V125BC [204]

Answer:

here's your answer - the angle of elevation

7 0

2 years ago

13 pts An object will apear the color that is: refracted reflected longest separated

Lady bird [3.3K]

Answer:

Reflected

Explanation:

Because light will reflect off the object into our eyes

6 0

3 years ago

Read 2 more answers

I need help with this please

Lesechka [4]

Q1- Urgent / Important

Q2- Writing a paper that is due in 3 hours

(others can wait as no serious consequences but you could fail n get bad mark if you don't complete the paper. It's a deadline issue.)

3 0

3 years ago

wariber [46]

<h2>Right answer: I and II only </h2>

If we already have the formula to find how temperature measured in degrees Fahrenheit, relates to a temperature in degres Celsius:

$C=(F-32)\frac{5}{9}$ (1)

We can know the formula to find how temperature measured in degrees Celsius, relates to a temperature in degres Fahrenheit, only by isolating F:

$F=(\frac{9}{5}C)+32$ (2)

Having both formulas, let’s begin:

I) If we want to prove that a temperature increase of 1 degree Fahrenheit is equivalent to a temperature increase of 5/9 degree Celsius:

Beginning with $1\ºF$ :

$C=(1\ºF-32)\frac{5}{9}=-17.22\ºC$

This means: $1\ºF=-17.22\ºC$

Now we are going to increase 1 degree Farenheit. In other words, we are going to use $2\ºF$ :

$C=(2\ºF-32)\frac{5}{9}=-16.66\ºC$

This means: $2\ºF=-16.66\ºC$

Calculating the difference between $-16.66\ºC$ and $-17.22\ºC$ :

$-16.66\ºC-(-17.22\ºC)=0,55\ºC$ >>>>This is equal to 5/9 degree Celsius, hence is correct

II) If we want to prove that a temperature increase of 1 degree Celsius is equivalent to a temperature increase of 1.8 degrees Fahrenheit:

Beginning with $1\ºC$ :

$F=(\frac{9}{5}1\ºC)+32$

$F=33.8\ºF$

This means: $1\ºC=33.8\ºF$

Now we are going to increase 1 degree Celsius. In other words, we are going to use $2\ºC$ :

$F=(\frac{9}{5}2\ºC)+32$

$F=35.67\ºF$

This means: $2\ºC=35.67\ºF$

Calculating the difference between $35.67\ºF$ and $33.8\ºF$ :

$35.67\ºF-33.8\ºF=1.8\ºF$ >>>>This is a proof of the statement, hence is also correct.

<h2 />

III) If we want to prove that a temperature increase of 5/9 degree Fahrenheit is equivalent to a temperature increase of 1 degree Celsius:

Beginning with $1\ºC$ :

$F=(\frac{9}{5}1\ºC)+32$

$F=33.8\ºF$

This means: $1\ºC=33.8\ºF$

Now we are going to add $\frac{5}{9}\ºF$ :

$33.8\ºF+\frac{5}{9}\ºF=34.35\ºF$

And use this value in the Celsius formula:

$C=(34.35\ºF-32)\frac{5}{9}=1.30\ºC$

This means: $1.30\ºC=34.35\ºF$

In other words: An increase in 5/9 degree Fahrenheit is equivalent to a temperature increase of 1.30 degree Celsius, not 1 degree Celsius.

Therefore this statement is incorrect.

4 0

3 years ago

Prove that the segment,joining the points of contact of two parallel tangents passes through the centre.

wariber [46]

Given: Two parallel tangents PQ and RS touch a circle C (O,r) at A and B respectively.
To prove: AB will pass through the centre O of the circle.
Construction:Draw a line OC parallel to RS.

Proof: PA || CO

=> ∠PAO + ∠COA =180 [Sum of the angles on the same side of a transversal is 180]
=> 90 + ∠COA = 180 [ ∠PAO = Angle between a tangent and radius = 90]
=> ∠COA = 90

Similarly, ∠COB = 90
Therefore, ∠COA + ∠COB = 90 + 90 = 180

Hence, AOB is a straight line passing through O.

5 0

3 years ago