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sasho [114]
2 years ago
11

What is the process of Asexual and Sexual reproduction of Jellyfish? Plz give BOTH answers!!

Biology
1 answer:
Kobotan [32]2 years ago
7 0

Answer:Jellyfish reproduction involves several different stages. In the adult, or medusa, stage of a jellyfish, they can reproduce sexually by releasing sperm and eggs into the water, forming a planula.

sexual is when there is a mom and dad and a sexual is when a single organism gives birth usually they look the exact same as the species  

Explanation:

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3 years ago
Part B
Serjik [45]

Answer:

Cell division is a process that makes our skin, tissues, muscles, sex cells. It is the building block of our body.

Explanation:

When parents cells ahs been divided into two or more than two daughter cells then it is called division of cells. The division of cells occur as a larger cell. When we talk about eukaryotic cells, these cells divided into two distinct types of the cells, the vegetative cells.

The daughter cells are the identical to the parents cells genetically. There are two types of division such as mitosis and meiosis. When parents cells divides in daughter cells and daughter cells divided further, this process called the cells cycle. The mitosis cell division occur interphase. Meiosis cell division occur in two phase meiosis I and meiosis II.

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Why is the sky blue? wrong answers only
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Maybe because you're feeling blue and the sky is a projection of your feelings.

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3 years ago
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"Bottom-up" (or "data-driven") mechanisms are Group of answer choices
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Answer: A. mechanisms for which activity is primarily triggered and shaped by the incoming stimulus information.

Explanation:

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4 0
3 years ago
In 1985 a biologist counted 750 pine trees in a 250 hectare forest. Using similar counting techniques, the biologist counted 1,2
Alisiya [41]

Answer:

Suppose that we have a given function f(x)

The average rate of change of the function between two values x₁ and x₂ is given by:

r = \frac{f(x_2) - f(x_1)}{x_2 - x_1}

a) We want to find the average (rate) of change on the size of population from 1985 to 1995.

We have that:

f(1985) = 750

f(1995) = 1500

Then we have:

r = \frac{1500 - 750}{1995 - 1985}  = 750/10 = 75

This means that the population of trees increases, in average, at a rate of 75 trees per year.

b) What is the density of trees each year that they were counted?

This will be equal to the quotient between the number of trees and the area.

1985: number of trees = 750 pines

         area = 250 ha

Then the density is:

D(1985) = (750 pines)/(250 ha) = 3 pines/ha

So 1985, there were 3 pines per hectare.

1990: number of trees = 1250 pines

         area = 250 ha

Then the density is:

D(1990) = (1250 pines)/(250 ha) = 5 pines/ha

1995: number of trees = 1500 pines

         area = 250 ha

The density is:

D(1995) = (1500 pines)/(250 ha) = 6 pines/ha

3) now we want to get the average change between 1985 and 1995 in the density, this will be:

r = \frac{D(1995) - D(1885)}{1995 - 1985}  = \frac{6 pines/ha - 3pines/ha}{10}  = 0.3 pines/ha

So, on average, each year the number of pines per hectare increases by 0.3

7 0
3 years ago
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