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2 years ago

Please help! im stuck on this question

Mathematics

1 answer:

Andreyy892 years ago

7 0

Answer:

Step-by-step explanation:

id say the answer is 6 or 9 :)

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What is the solution to 3x²+x+10=0

e-lub [12.9K]

Answer:

x = - 1/6 + √-119/6, and, - 1/6 - √-119/6

Step-by-step explanation:

Using the quadratic formula which is: - b ± √b² - 4ac / 2a

a = 3, b = 1, c = 10

- 1 ± √1² -4 * 3 * 10 / 2 * 3

- 1 ± √1 - 120 / 6

-1 ± √-119 / 6

= -1/6 + √119/6, or - 1/6 - √-119/6

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3 years ago

The eagles won 60% of the games they played last season. They played 15 games. How many games did they win?

Romashka-Z-Leto [24]

9 games multiply 0.6 to 15

8 0

3 years ago

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Give a 98% confidence interval for one population mean, given asample of 28 data points with sample mean 30.0 and sample standar

klio [65]

We have a sample of 28 data points. The sample mean is 30.0 and the sample standard deviation is 2.40. The confidence level required is 98%. Then, we calculate α by:

$\begin{gathered} 1-\alpha=0.98 \\ \alpha=0.02 \end{gathered}$

The confidence interval for the population mean, given the sample mean μ and the sample standard deviation σ, can be calculated as:

$CI(\mu)=\lbrack x-Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}},x+Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}}\rbrack$

Where n is the sample size, and Z is the z-score for 1 - α/2. Using the known values:

$CI(\mu)=\lbrack30.0-Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}},30.0+Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}}\rbrack$

Where (from tables):

$Z_{0.99}=2.33$

Finally, the interval at 98% confidence level is:

$CI(\mu)=\lbrack28.94,31.06\rbrack$

4 0

1 year ago

I need help like really bad

serg [7]

Answer:

Step-by-step explanation:

14/15 is less than 7/5

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3 years ago

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Are the two triangles below .similar?

kozerog [31]

Yes, because both of them have a 70 degree angle on T and W

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3 years ago