The answer to this question would be letter B (0,2)
Answer:
x ≥6
Step-by-step explanation:
Given the product:
√(x-6)*√(x+3)
The function has to be defined if x ≥0
Hence;
√(x-6)*√(x+3)≥0
Find the product
√(x-6)(x+3)≥0
Square both sides
(x-6)(x+3)≥0
x-6≥0 and x+3≥0
x≥0+6 and x ≥0 - 3
x ≥6 and x ≥-3
Hence the required inequality is x ≥6
The formula of interest is
A = (1/2)r²·θ
You have r = 9 m, θ = 3π/5. Then the area is
A = (1/2)(9 m)²(3π/5) = 24.3π m²
The sector area is ...
A ≈ 76.3 m²
Experimental because he's actually doing it.
