All categories

3 years ago

(1,2) and parallel to 3x+4y=12

Mathematics

1 answer:

zheka24 [161]3 years ago

3 0

Answer:

y=-3/4x+10/4

Step-by-step explanation:

1) Change given equation to slope intercept form:

3x+4y=12

4y=12-3x

y=3-(3/4)x

y=-(3/4)x+3

2) Parallel lines have the same slope, so the first part of the equation is:

y=-(3/4)x+b

3) To find b, we plug in y=2 and x=1 given the prompt:

2=-(3/4)(1)+b

2=-3/4+b

2 3/4=b

10/4=b

4) Therefore, the correct equation is:

y=-3/4x+10/4

You might be interested in

Two more than the quotient of a number and 5 is 8. use variable w for the unknown number.

KengaRu [80]

Answer:

The answer is that w = 30

Step-by-step explanation:

To find this, we start by modeling the equation.

w/5 + 2 = 8

We know it looks like this since they say quotient, which means division problem.

w/5 + 2 = 8

w/5 = 6

w = 30

7 0

3 years ago

R+b=7 3.75r+2.75b=22.25

stiv31 [10]

Answer:

Step-by-step explanation:

hello :

r+b=7... (*)

3.75r+2.75b=22.25.... (**)

use (*) : r = 7 - b

put this value in (**) :

3.75(7 - b)+2.75b = 22.25

26.25 -375b +2.75b = 22.5

-375b +2.75b = 22.5 - 26.25

- b = -3.75

so : b = 3.75

but : r = 7 - b

r = 7 - 3.75

r = 3.25

6 0

3 years ago

6x – 2y = 10 2x + 3y = 51 solving the first equation above for y gives:

Masja [62]

The first equation is 6x - 2y = 10. To solve for y, you will use inverse (opposite) operations to undo what is happening to y. Please see the steps below for the work.

6x - 2y = 10
-6x -6x
-2y = (-6x + 10)
-2 -2
y = 3x - 5

6 0

3 years ago

Of the zeroes have a multiplicity of 2.

CaHeK987 [17]

Answer: None the zeroes have a multiplicity of 2.

Step-by-step explanation: i took the test

6 0

3 years ago

Read 2 more answers

dos aviones parten de una ciudad con direcciones S32°E y E57°N¿ cuál es el angulo que forma sus direcciones?

Elan Coil [88]

Answer:

El ángulo formado entre las dos direcciones es aproximadamente 115º.

Step-by-step explanation:

Las direcciones dadas en el enunciado significan lo siguiente:

S32ºE - 32º al este del sur.

E57ºN - 57º al norte del este.

Vectorialmente hablando, cada dirección es la siguiente:

S32ºE

$A(x,y) = (\sin 32^{\circ}, -\cos 32^{\circ})$

$A(x,y) = (0.530, -0.848)$

E57ºN

$B(x,y) = (\cos 57^{\circ},\sin 57^{\circ})$

$B(x,y) = (0.545, 0.839)$

El ángulo formado entre los dos vectores unitarios ( $\theta$ ), medido en grado sexagesimales, puede determinarse mediante la siguiente ecuación vectorial:

$\theta = \cos^{-1} \frac{A\,\bullet \,B}{\|A\|\cdot \|B\|}$

Donde:

$\|A\|$ - Norma de $A(x,y)$ .

$\|B\|$ - Norma de $B(x,y)$ .

Si sabemos que $A(x,y) = (0.530, -0.848)$ , $B(x,y) = (0.545, 0.839)$ , $\|A\| = 1$ y $\|B\| = 1$ , entonces el ángulo formado entre los dos vectores es:

$\theta = \cos^{-1} \frac{(0.530)\cdot (0.545)+(-0.848)\cdot (0.839)}{(1)\cdot (1)}$

$\theta \approx 115^{\circ}$

El ángulo formado entre las dos direcciones es aproximadamente 115º.

4 0

3 years ago