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katen-ka-za [31]
3 years ago
11

Justin packed two suitcases for his trip and compared the weights of the items he packed in each of the suitcases. A number line

goes from 0 to 36. Suitcase 1's whiskers range from 4 to 30, and the box ranges from 8 to 12. A line divides the box at 9. Suitcase 2's whiskers range from 2 to 20, and the box ranges from 5 to 18. A line divides the box at 7. Which statement is true about the box plots? The data for suitcase 1 have an outlier, but the data for suitcase 2 does not. The data for suitcase 2 have a greater median than the data for suitcase 1. The data for suitcase 1 has a greater interquartile range than the data for suitcase 2. The data for suitcase 2 has a greater range than the data for suitcase 1.
Mathematics
1 answer:
BabaBlast [244]3 years ago
4 0

Answer:

The correct option is;

The data for suitcase 1 have an outlier but the data for suitcase 2 does not

Step-by-step explanation:

Range of a box plot

Interquartile range (IQR) for bot suitcases we have

Here we have for suitcase 1

IQR = Q₃ - Q₁ = 12 - 8 = 4

For suitcase 2

IQR = Q₃ - Q₁ = 18 - 5 = 13

Lower outlier = Q₁ - 1.5×IQR

Higher outlier = Q₃ + 1.5×IQR

For suitcase 1 we have;

Lower outlier = 8 - 1.5×4 = 2 (No lower outlier)

Higher outlier = 12 + 1.5×4 = 18

Hence, whereby the whiskers range from 4 to 30, suitcase 1 has a higher outlier

For suitcase 2 we have;

Lower outlier = 5 - 1.5×13 = -14.5  (No lower outlier)

Higher outlier = 18 + 1.5×13 = 37.5

Hence, whereby the whiskers range from 2 to 20, suitcase 2 has no outlier.

Therefore, the correct option is the data for suitcase 1 have an outlier but the data for suitcase 2 does not.

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ser-zykov [4K]

First let's convert the decimal numbers to mixed numbers:

\begin{gathered} 3.4=3+0.4=3+\frac{4}{10}=3+\frac{2}{5}=3\frac{2}{5} \\ 1.75=1+0.75=1+\frac{75}{100}=1+\frac{3}{4}=1\frac{3}{4} \\ 2.25=2+0.25=2+\frac{25}{100}=2+\frac{1}{4}=2\frac{1}{4} \end{gathered}

Now, adding all the numbers, we have:

\begin{gathered} (3+\frac{2}{5})+(3+\frac{1}{5})+(1+\frac{3}{4})+(2+\frac{1}{4})+(1+\frac{7}{10}) \\ =(3+3+1+2+1)+(\frac{2}{5}+\frac{1}{5}+\frac{3}{4}+\frac{1}{4}+\frac{7}{10}) \\ =10+(\frac{3}{5}+1+\frac{7}{10}) \\ =11+(\frac{6}{10}+\frac{7}{10}) \\ =11+\frac{13}{10} \\ =12+\frac{3}{10}=12\frac{3}{10} \end{gathered}

So the correct option is B.

8 0
1 year ago
Someone help me I need to understand
Firlakuza [10]

Answer:

Easy you describe the sum of each arithmetic series. GOOD LUCK

Step-by-step explanation:

3 0
4 years ago
X/3+10=14 what would x equal?
Dmitry [639]

Answer:

x=12

Step-by-step explanation:

(x/3)+10=14

(x/3)+10-10=14-10

(x/3)=4

x/3*3=4*3

x=12

6 0
3 years ago
What is the missing number? x-3=72?<br> Need help
AlladinOne [14]
Add 3 to 72... so 3 plus 72 is 75

X=75
8 0
3 years ago
Read 2 more answers
Find the difference 67/8 - 43/8=
dmitriy555 [2]

Answer: 3

Step-by-step explanation:

Since the denominator of the two fractions are already the same, we do not have to alter the fractions at all

Because the denominators are the same, all we have to worry about is the numerator, so take 67 and subtract 43 from it to get 24

\frac{67}{8} -\frac{43}{8} =\frac{24}{8}

As you know, 24/8 = 3, and that would be your final answer

7 0
3 years ago
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