If the perimeter was 34 and the area is 72 what is the length and width?
1 answer:
Answer:
xy = 72
2x + 2y = 34 (Im assuming uts a rectangle or square)
2 (72/y) + 2y = 34
144 + 2y^2 = 34y
2y^2 - 34y + 144 = 0
y = 9 or 8
So the length is 9 and width = 8
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